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AleksAgata [21]
3 years ago
5

Does this set of ordered pairs represent a function? Why or why not. Don’t need a step to step just the answer

Mathematics
2 answers:
Charra [1.4K]3 years ago
6 0

Answer:

Choice D is correct. Every x-value corresponds to exactly one y-value.

Step-by-step explanation:

We have given the set of ordered pairs :

{ (-5,-5) ,(-1,-2),(0,-2),(3,7),(8,9) }

We have to explain that is this set represent a function or not?

Function is a rule that assigns each input exactly one output.

In the set, each value of x has unique value of y.

From the definition of function,this set represent a function because each input has a single output.

Every x-value corresponds to exactly one y-value.

Scrat [10]3 years ago
3 0

Answer:

D. Yes,because every x-value corresponds to exactly one y-value.

Step-by-step explanation:

The given ordered pairs are;

{(-5,-5),(-1,-2),(0,-2),(3,7),(8,9)}

We do not have the same x-value corresponding to more than one y-value.

We can see from the ordered pairs that every x-value corresponds to exactly one y-value.

Therefore the graph of this relation will pass the vertical line test.

You might be interested in
4:X is equivalent to 24:12<br> X=???
Elena-2011 [213]

Answer:

X=2

Step-by-step explanation:

Ratios

4:x = 24:12

24:12 reduced is 2:1

Therefore we can see x must be half of 4.

So the answer is 2

Hope this helps! :)

pls mark brainiest

6 0
3 years ago
Read 2 more answers
Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

   Determinant       16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

                                                                                 = -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

6 0
3 years ago
The system of equations
cupoosta [38]

Answer:

z = -12

Step-by-step explanation:

The given system of equations is:

xy/(x + y) = 1 ...........................(1)

xz/(x + z) = 2...........................(2)

yz/(y + z) = 3...........................(3)

From (1): x + y = xy

=> y = xy - x

y = x(y - 1)

x = y/(y - 1).......................................(4)

From (2): 2(x + z) = xz

=> 2x + 2z = xz

2x = xz - 2z

2x = z(x - 2)

z = 2x/(x - 2) ....................................(5)

From (3): 3(y + z) = yz

=> 3y + 3z = yz

3y = yz - 3z

3y = z(y - 3)

z = 3y/(y - 3)....................................(6)

Comparing (5) and (6)

2x/(x - 2) = 3y/(y - 3)

2x(y - 3) = 3y(x - 2)

2xy - 6x = 3xy - 6y

6(y - x) = xy .................................(7)

But from (1): xy = x + y

Using this in (7), we have

6(y - x) = x + y

6y - y - 6x - x = 0

5y - 7x = 0

5y = 7x

x = 5y/7................................................(8)

Using this in (4)

5y/7 = y/(y - 1)

1/(y - 1) = 5/7

(y - 1) = 7/5

y = 1 + 7/5

y = 12/5..........................................(9)

Using this in (8)

x = 5(12/5)/7 = 12/7 .......................(10)

Using (10) in (5)

z = 2x/(x - 2)

z = 2(12/7) ÷ (12/7 - 2)

= 24/7 ÷ -2/7

= 24/7 × (-7/2)

= -24/2 = -12

z = -12.

4 0
3 years ago
What are the differences between pyramids and cones?
stepan [7]

Answer:

Pyramids are triangular in shape with a sided shape, whereas cones have circular bases that merely adjoin at a point.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the domain and range?
Pie

Answer:

Domain: {-6, -2, -1, 1, 3, 6}

Range: {-6, -2, -1, 0, 3}

Step-by-step explanation:

to find the domain of a function, you look at all the possible x-values. this means you look at all the points, and see what their x-values are.

for example, the first point on the left is at (-6, -1). this means that -6 is in the domain. continue doing this for all the points, and you get {-6, -2, -1, 1, 3, 6}

to find the range of a function, it's just like domain but with y-values.

for example, for the leftmost point, it's at (-6, -1) so -1 is part of the range. continuing this with all the points, you get {-6, -2, -1, 0, 3}

5 0
2 years ago
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