Answer:
void print_popcorn_time(int bag_ounces){
if(bag_ounces < 3){
cout<<"Too small"<<endl;
}else if(bag_ounces > 10){
cout<<"Too large"<<endl;
}else{
cout<<(6 * bag_ounces)<<"seconds"<<endl;
}
}
Explanation:
The function is the block of the statement which performs the special task.
For checking the condition in the program, the if-else statement is used.
It can check the condition one or two but if we want to check the more than two different conditions then the continuous if-else statement is used.
syntax of continuous if else:
if(condition){
statement;
}else if(condition)
statement;
}else{
statement;
}
In the question, there are three conditions;
1. bag_ounces is less than 3
2. bag_ounces greater than 10
3. else part.
we put the condition in the above if-else statement and print the corresponding message.
Answer:
A.
Explanation:
Ebooks are typically only text, which is smal.
However, a Photo can be very small too, so the answer is not definitive.
Answer:
Number.
Letter is for columns, Number is for rows.
For example to find the cell on the fifth row, and 1st column, it would be A5.
Answer:
The correct answer to the following question will be "Peak capacity" and "Bandwidth starvation".
Explanation:
Peak capacity has been used to characterize the gradient aqueous phase separation efficiency or performance. It represents the overall conceptual number of operations or components which can be isolated consistently with something like a given set of analytical circumstances and column with
⇒ Rs =1 (Figure 1 and Equation 1)
Certain traffic competing at its policies for the available or unused bandwidth will theoretically enable classes with lower value rates to starve to bandwidth.
Due to these activities, Sharon is concerned about "Bandwidth starvation" and "Peak capacity".
Answer:
The correct answer to the following question will be "n logn".
Explanation:
- Time Complexity should be the same as the whole last particular instance, just the log base keeps changing with three.
- Throughout the circumstance of separating 2 arrays, we want one correlation. however, for splitting between 3-way arrays, will require 2 comparisons to sort.
- However, after breaking the array into 3, we can lower the number of transfers by growing the comparison. So the time complexity would then persist the same, but the log should get base 3 as we've classified into different parts.
So the time complexity will be:
⇒ 
⇒ 
