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yan [13]
4 years ago
14

222+203 is it compatible or rounding

Mathematics
2 answers:
snow_lady [41]4 years ago
8 0
I belive it is rounding
antiseptic1488 [7]4 years ago
5 0
For 222+203 it is best to start with 2+3=5
then 20+00=20
then add the two totals together 20+5=25
next 200+200=400
and last 400+25=425
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Effectus [21]
D= 14.5 I promise dawg
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Please help! What is the area of this figure?<br><br> Answer and explanation please! &lt;3
andriy [413]

Answer:

19 units²

Step-by-step explanation:

Divide into three shapes:

Large rectangle BEFA

Large triangle - BCE

Small triangle - CDE -

BEFA = 4x3 = 12

BCE = 1/2x4x2 = 4

CDE = 1/2x3x2 = 3

12+4+3=19

6 0
3 years ago
What is the value of this expression when 12-1 and y=22<br> 42
lubasha [3.4K]

Answer:

11

Step-by-step explanation:

12-1=11

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3 years ago
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If x+4 Is a Factor Of The Polynomial x³-x²-14x+24 ,Then Find Other Factors.​
Allisa [31]

Answer:

(x - 3) and (x - 2)

Step-by-step explanation:

Using the method of long division to divide the polynomial by x + 4

               

                   x² - 5x + 6

                 -------------------------------

x + 4   |  x³ - x² - 14x + 24

             x³ + 4x²

             ---------------------------

                  - 5x² - 14x + 24

                   - 5x² - 20x

              -------------------------------

                               6x + 24

                               6x + 24

                --------------------------------

                              0        0

The quotient is x² - 5x +  6 = (x - 2)(x - 3)

x³ - x² - 14x + 24 = (x - 2)(x - 3)(x + 4) ← in factored form

 

          |

6 0
3 years ago
Use the parabola tool to graph the quadratic function f(x)=x2−12x+27. Graph the parabola by first plotting its vertex and then p
alina1380 [7]

Answer:

vertex is (6 , -9)

points are (9,0) and (3,0)

Step-by-step explanation:

Given quadratic function f(x)=x^2-12x+27

We have to plot the given quadratic function.

Consider the Given quadratic function f(x)=x^2-12x+27

The general form of quadratic function  is given f(x)=a(x-h)^2+k

Where, (h, k)  is vertex , given  h =\frac{-b}{2a} and k = f(h)  

Thus, for given quadratic function f(x)=x^2-12x+27

a = 1 , b= -12 , c = 27

Thus,

h =\frac{-b}{2a}=\frac{12}{2}=6

k = f(h) that is f(12) = (6)^2 - 12× 6 +27 = 36 - 72 + 27 = - 9

Thus, given  quadratic function f(x)=x^2-12x+27 in standard form is f(x)=(x-6)^2-9  

Thus, vertex is (6 , -9)

For second point put f(x)=0  , we get,

f(x)=(x-6)^2-9=0  

\Rightarrow (x-6)^2-9=0  

\Rightarrow (x-6)^2=9  

\Rightarrow (x-6)=\pm 3  

\Rightarrow x= 6\pm 3  

Thus, \Rightarrow x=6+3=9 and \Rightarrow x=6-3=3  

thus, points are (9,0) and (3,0)

Graph is attached below.

5 0
4 years ago
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