Question

A tennis court for singles play is 78 feet long and 27 feet wide. Part 1 out of 3 The court for doubles play is 9 feet wider than the court for singles play. How much more area is covered by the tennis court used for doubles play? The tennis court used for doubles play covers square feet more area than the court used for singles play.

Answer 1

Answer:

702 ft^2

Step-by-step explanation:

Steps to answering this question

1. determine the area of the singles court

area of a rectangle = length x width

27 x 78 = 2106 ft^2

2. Determine the width of the doubles court

27 + 9 = 36FT

3. Calculate the area of the doubles court

area of a rectangle = length x width

78 x 36 = 2808 ft^2

Find the difference in areas

2808 - 2106 = 702 ft^2