3 years ago

What is the coefficient of q in the sum of (2q - 3) and (-1q - r)?

Mathematics

1 answer:

Alex787 [66]3 years ago

8 0

Answer:

The Coefficient is 3

Step-by-step explanation:

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Are the graphs of the lines in the pair parallel? Explain.<br><br> y = 3/7x + 11<br> –3x + 7y = 13

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Step-by-step explanation:

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Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

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3 years ago

what is the distance between point (-5, -2) and point (8, -3) rounded to the nearest tenth? will appreciate all the help

Sidana [21]

$\text {Distance =} \sqrt{((Y_2-Y_1)^2+(X_2-X_1)^2}$

$\text {Distance =} \sqrt{((-3-(-1))^2+(8-(-5))^2}$

$\text {Distance =} \sqrt{(-1)^2+(13)^2}$

$\text {Distance =} \sqrt{(1+169}$

$\text {Distance =} \sqrt{170}$

$\text {Distance =} 13.0 \text { units}$

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