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3 years ago

What is 150 times 100

Mathematics

1 answer:

Elis [28]3 years ago

5 0

Answer:

100×150

it's the answer

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The m∠P is three less than twice the measure of ∠Q. If ∠P and ∠Q are supplementary angles, find the measures of both angles.

notka56 [123]

Answer:

m∠P =119

m∠Q = 61

Step-by-step explanation:

m∠P = 2(∠Q)-3 or p=2(q)-3

supplementary angles so they combine to equal 180!

soooooo we can take

q+p=180

input what p equals and you get

q+ 2(q)-3=180

3q-3=180

3q=183

q=61

now we have what m∠Q is, so just subtract that from 180 to get m∠P

180-61=119

7 0

3 years ago

Lynn can type 1,650 words in 30 minutes. <br> What is her typing rate, in words per minute?

Marianna [84]

55 words per minute

1650/30 = 55

7 0

2 years ago

Read 2 more answers

The sum of two numbers is 49 and the difference is 25 . What are the numbers?

OLEGan [10]

Answer:

x = 37 y = 12

Step-by-step explanation:

Let x be one number

Let y = other number

x+y = 49

x-y = 25

Add the equations together

x+y = 49

x-y = 25

---------------

2x = 74

Divide by 2

2x/2 = 74/2

x =37

x+y = 49

37+y = 49

Subtract 37 from each side

37+y-37 = 49-37

y = 12

4 0

3 years ago

Han can run 100 meters in 20 seconds how long will it take him to run 3000 metres

Juliette [100K]

Answer:

600 seconds

Step-by-step explanation:

In this case we have to calculate the speed;

Speed = Distance/Time

Speed = 100/20 = 5 mph

Next to get our answer we have to calculate the amount of time

Time = Distance/Speed

Time = 3000/5 = 600 seconds

4 0

3 years ago

A three inch diameter pulley on an electric motor that runs at 1800

Bezzdna [24]

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ. Then the tangential speed V is related to angular speed ω as:

$V=R\omega$

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

$\omega_1 R_1 = \omega_2 R_2\\$

$\omega_2 = \omega_1 \frac{R_1}{R_2} =1800RPM* \frac{3}{6}= 900RPM$

We need to convert RPM to radias per minute. One revolution is 2π radians, then:

$\omega_1 = 1800*2\pi \frac{radians}{min} = 11,309.7\frac{radians}{min}$

$\omega_2 = 5654.7 \frac{radians}{min}$

The saw rotates with the same angular speed as the 6 inch pulley: 900RPM

3 0

3 years ago