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Artyom0805 [142]

3 years ago

13

Find the midpoint of AC is at -2 and C is at 3 on a number line

1 answer:

Bad White [126]3 years ago

3 0

2c3 Because when you look at it when you look at the question if I do that and then you were at the AC is at the two and see is that the three on the number line then you would add that on and you’ll get your answer

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How to make an equation out of perimeter and area

Natasha2012 [34]

Where P = perimeter, L = length, W = width, and A = area:

A = LW
P = 2(LW)

Hope this helped! :)

7 0

4 years ago

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I am a 3 digit positive number. The sum of my digits is 18. My middle digit is the product of -2 and -4. My first digit is 3^2.

Vlad1618 [11]

Let x be the first digit.
Let y be the second digit.
Let z be the third digit.

x+y+z=18

y= (-2)(-4)
y= 8

x= 3^2
x= 9

Therefore z=1.

The number is
= 100x+10y+z
= 100(9)+10(8)+(1)
= 981

3 0

2 years ago

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Please help asap, will mark Brainliest xoxo

IgorC [24]

Answer/Step-by-step explanation:

Given, $b(x) = (\frac{6}{7})^{x}$

The table for the function are:

When x = -2

$b(-2) = (\frac{6}{7})^{-2}$

$b(-2) = \frac{1}{(\frac{6}{7})^{2}}$

$b(-2) = \frac{1}{(\frac{36}{49})}$

$b(-2) = 1*\frac{49}{36}$

$b(-2) = \frac{49}{36}$

When x = -1

$b(-1) = (\frac{6}{7})^{-1}$

$b(-1) = \frac{1}{(\frac{6}{7})}$

$b(-1) = 1*\frac{7}{6}$

$b(-2) = \frac{7}{6}$

When x = 0

$b(0) = (\frac{6}{7})^{0}$

$b(0) = \frac{6^0}{7^0}$

$b(0) = \frac{1}{1}$

$b(0) = 1$

When x = 1

$b(1) = (\frac{6}{7})^{1}$

$b(1) = \frac{6}{7}$

When x = 2

$b(2) = (\frac{6}{7})^{2}$

$b(2) = \frac{6^2}{7^2}$

$b(2) = \frac{36}{49}$

3 0

3 years ago

The balance in a bank account after t years is given by the equation B = 2500(1.015)

melomori [17]

The answer to you question is b = 2537.5 I think

7 0

3 years ago

The upper-left coordinates on a rectangle are (-4, 4) and the upper-right coordinates are (4, 4). The rectangle has an area of 8

ale4655 [162]

Answer:

I need the questions

Step-by-step explanation:

6 0

4 years ago

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