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Artyom0805 [142]
3 years ago
13

Find the midpoint of AC is at -2 and C is at 3 on a number line

Mathematics
1 answer:
Bad White [126]3 years ago
3 0
2c3 Because when you look at it when you look at the question if I do that and then you were at the AC is at the two and see is that the three on the number line then you would add that on and you’ll get your answer
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On a coordinate plane, a line is drawn from point K to point J. Point K is at (160, 120) and point J is at (negative 40, 80). Wh
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The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is  (85, 105).

Given

On a coordinate plane, a line is drawn from point K to point J. Point K is at (160, 120) and point J is at (negative 40, 80).

<h3>Coordinates</h3>

The coordinates point any point can be found by using the following formula.

\rm X=\dfrac{m}{m+n}(x_2-x_1)+x_1\\\\ Y=\dfrac{m}{m+n}(y_2-y_1)+y_1

The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is;

\rm X=\dfrac{m}{m+n}(x_2-x_1)+x_1\\\\ X = \dfrac{3}{3+5}(-40-160)+160\\\\ X = 3 \times (-25)+160\\\\\X = -75+160\\\\ X = 85\\\\\ Y=\dfrac{m}{m+n}(y_2-y_1)+y_1\\\\ Y=\dfrac{3}{3+5}(80-120)+120\\\\Y =- 3\times 5 +`120\\\\Y=-15+120\\\\Y=105

Hence, the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is  (85, 105).

To know more about co-ordinates click the link given below.

brainly.com/question/13847533

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