(0,1)(2,7)
slope(m) = (7-1) / (2-0) = 6/2 = 3
y = mx + b
slope(m) = 3
use either of ur points...(0,1)....x = 0 and y = 1
now sub and find b, the y int
1 = 3(0) + b
1 = b
so ur equation is : y = 3x + 1....or 3x - y = -1
Answer:
<h2>
70cm/s</h2>
Step-by-step explanation:
Area of a square with side of length L is expressed as A = L². The rate at which the area is increasing will be expressed as dA/dt.
dA/dt = dA/dL * dL/dt where
dL/dt is the rate at which each side of the square is increasing.
Since dA/dL = 2L, dA/dt = 2L dL/dt
Given dL/dt = 5cm/s and the Area of the square = 49 cm²
49 = L²
L = √49
L = 7cm
dA/dt = 2(7) * 5
dA/dt = 14*5
dA/dt = 70cm/s
The rate at which the area of the square is increasing is 70cm/s
You can easily add while numbers but with decimals, if the point is put in the wrong place then you’ll change the entire number