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3 years ago

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Rachel is planning to run an average of 6.4 miles over three consecutive days. On the first day, she ran 6.6 miles, and on the s

econd day, she ran 6.5 miles. What is the maximum number of miles Rachel can run on the third day without going over the planned average of 6.4 miles per day?

1 answer:

-BARSIC- [3]3 years ago

7 0

6.6+6.5=13.1 6.4*3=19.2 19.2-13.1=6.1 she can run 6.1 miles

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3 years ago

Select the point that is a solution to the system of inequalities

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<h2>Hello!</h2>

The answer is:

The point that is a solution to the system of inequalities is C(4,2).

<h2>Why?</h2>

To find the point that is a solution to the system of inequalities, we need to evaluate it into the given inequalities. If the point is a solution to the system of inequalities, both inequalities will be satisfied.

We are given the inequalities:

$y\leq 2x-2$

$y\leq x^{2} -3x$

So, substituting the given points into the given inequalities, we have:

- A. (2,1)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\1\leq 2*(2)-2\\\\1\leq 4-2\\\\1\leq 2$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$1\leq (2)^{2} -3(2)$

$1\leq (2)^{2} -3(2)$

$1\leq 4 -6$

$1\leq -2$

Therefore, since 1 is not less or equal to -2, the point A(2,1) is not a solution to the system of inequalities.

- B. (-2,-1)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\-1\leq (-2)*(2)-2\\\\-1\leq -4-2\\\\-1\leq -6$

Substituting into the second inequality, we have:

$y\leq x^{2} -3x$

$-1\leq (-2)^{2} -3(-2)$

$-1\leq 4 +6$

$-1\leq 10$

Therefore, since -1 is not less or equal to -6, the point B(-2,-1) is not a solution to the system of inequalities.

- C. (4,2)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\2\leq (4)*(2)-2\\\\2\leq 8-2\\\\2\leq 6$

Substituting into the second inequality, we have:

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Therefore, since 2 is less than 6, and 2 is less than 4, the point B(4,2) is a solution to the system of inequalities.

- D(1,3)

Substituting into the first inequality, we have:

$y\leq 2x-2\\\\3\leq (1)*(2)-2\\\\3\leq 2-2\\\\3\leq 0$

Substituting into the second inequality, we have:

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$3\leq (1)^{2} -3(1)$

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$3\leq -2$

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Have a nice day!

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The best and the most correct answer among the choices provided by the question is the first choice. The pair of angles that are vertical is <span>∠KRC and ∠CRH ∠MRC and ∠KRM ∠ERT. </span>I hope my answer has come to your help. God bless and have a nice day ahead!

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