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maxonik [38]
3 years ago
12

William Arsenio is remodeling his home in order to save money he is upgrading the plumbing himself he needs 27 pieces of copper

tubing each 2/9 of a foot-long if he has a 8 foot piece of tubing will that be enough? How much more does he need or how much tubing will be left over?
Mathematics
1 answer:
Reptile [31]3 years ago
6 0

Answer:

Yes.

2 feet

Step-by-step explanation:

Pieces of copper that Arsenio needs in total = 27 pieces

Length of each piece of copper tubing that he needs = 2/9 foot

Length of available tubing = 8 foot

Since, the length of each piece is 2/9 foot, the length of 27 pieces would be:

\frac{2}{9} \times 27 = 6

This means, Arsenio needs 6 feet in total for the copper tubing. Since he got 8 feet in total, he has sufficient amount of tubing available.

After making the 27 pieces, he will be left with 8 - 6 = 2 feet of tubing.

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3 years ago
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= (x^18y^24)/(x^2y^2)

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points. Rachel scored 78 p
Artemon [7]

Answer:

Keenan's z-score was of 0.61.

Rachel's z-score was of 0.81.

Step-by-step explanation:

Z-score:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.

This means that X = 80, \mu = 77, \sigma = 4.9

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 77}{4.9}

Z = 0.61

Keenan's z-score was of 0.61.

Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.

This means that X = 78, \mu = 75, \sigma = 3.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{75 - 78}{3.7}

Z = 0.81

Rachel's z-score was of 0.81.

6 0
3 years ago
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denis-greek [22]
If a = 10, then the equation would be 10+6.
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