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Alona [7]
3 years ago
11

Graph the lines 2y+3x=8 on the graph below (solve for y and graph)

Mathematics
2 answers:
Harman [31]3 years ago
8 0

Answer:

y = 4 - 3x/2

Step-by-step explanation:

Sladkaya [172]3 years ago
3 0

Step-by-step explanation:

y=4-3/2

I hope it's correct hehehe

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3(9-8x-4x)+8(3x+4)=11
Papessa [141]
3(9 - 8x - 4x) + 8(3x + 4) = 11

3(9 - 12x) + 8(3x + 4) = 11

27 - 36x + 24x + 32 = 11

59 - 12x = 11

-12x = 11 - 59 

-12x = -48

x = 4

hope this helps, God bless!
4 0
3 years ago
(15-3)÷12+1<br>How to divide this without using a remainder?​
Julli [10]

Answer:

If you solved this, it wouldn't have a remainder. First you would solve the numbers in the parenthesis, (15 - 3), which is 12. Now it should look like, 12 ÷ 12 + 1. Next you divide 12 by 12 and that equals 1. And all you need to do now is add 1 + 1, which is 2. So your answer will be 2.

8 0
3 years ago
Read 2 more answers
you wish to purchase dog food foe your kennel. you find 2 equal brands. bowser dog food comes in 50lb. bags for 32.50 per bag .
evablogger [386]

Answer:

Woof Woof dog food is a better deal. It costs $1.48 per pound.

Bowser dog food costs $1.54 per pound.

6 0
3 years ago
The area of a trapezoid is
horrorfan [7]

Answer:

<h2>The answer is 15cm</h2>

Step-by-step explanation:

Let b be the length of the second parallel side

Area of a trapezium is given by

A =  \frac{1}{2} (a + b)h

where

h is the height

a and b are the parallel sides

From the question

Area = 230 cm²

height = 20cm

one of parallel side / a = 8 cm

Substitute the values into the above formula and solve for b

That's

230 =  \frac{1}{2} ( 8 + b) 20

Reduce the fraction with 2

That's

230 = (8 + b) \times 10

Expand the terms

That's

230 = 80 + 10b

10b = 230 - 80 \\ 10b = 150

Divide both sides by 10

We have the final answer as

<h3>b = 15cm</h3>

Hope this helps you

4 0
2 years ago
Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ
solong [7]

Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line  x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

3 0
3 years ago
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