The circle below is centered at -1, 1 and has a radius of 3. what is its equation
1 answer:
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Acc. to midpoint theorem,
15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x
WZ= 4x-15
=4*6-15
=24-15=9
15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x
WZ= 4x-15
=4*6-15
=24-15=9