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2 years ago

Please help as soon as possible

Mathematics

1 answer:

Crank2 years ago

6 0

Answer:

$9 \times 3 = 27 \\ 15 \times 6 = 90 \\ = 30.255 \\ 49 \times 3.14 = 153.86 \\ 153.86 + 30.255 + 27 = 211.115$

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Answer it pls and no memes

aev [14]

Answer:

There's two of them, of which are the 3rd and 5th option

Step-by-step explanation:

The formula for calculating a prism is length times width, times the height because it is a 3d object. Length times width is the same as B(base), so those two are the exact same. Don't let that fool you.

Here's a little abstract context:

You've got one loaf of bread right? Well, pretend it's 3 inches by 4 inches. You have one slice, one layer, with 12 inches squared as its area. To make it a loaf, you stack the layers up by multiplying that slice of bread by the value of h.

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3 years ago

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A biker moves 2.5 times faster than a walker. They started moving simultaneously in the same direction from the same point. In t

saveliy_v [14]

Answer:

The speed of the biker is 15

Step-by-step explanation:

First, you call the speed of the walker x, and the speed of the biker 2.5x.

Then you know that speed times time equals distance, so you set up and equation. You do x times 2, which is 2x, and then 2.5x times 2, which is 5x. Then, since the distance between them is 18 miles, the equation would be 5x-2x=18. You would get 3x=18, and x is 6. So 6 is the speed of the walker, and 6 times 2.5 = 15, so the speed of the biker is 15.

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3 years ago

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3(x-5)=2(x-10) Solce for X

stira [4]

Answer: X = -5

Step-by-step explanation:

3(x-5)=2(x-10)

3x - 15 = 2x -20

3x = 2x -5

x = -5

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3 years ago

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Solve the differential equation y prime equals the product of 2 times x and the square root of the quantity 1 minus y squared .

MatroZZZ [7]

Answer:

1. y = sin(x²+C)

2. see below

Step-by-step explanation:

1. $\frac{dy}{dx} = 2x\sqrt{1-y^2}$

separation of variables

$\frac{dy}{\sqrt{1-y^2} } = 2xdx$

integration both sides $\int\frac{dy}{\sqrt{1-y^2} } = \int2xdx$

you should get :

$sin^{-1} (y) = x^2+C$ remember constant of integration!!

2. y = sin(x²+C)

3 = sin(0+C)

y(0) = 3 does not have a solution because our sin graph is not shifted vertically or multiplied by a factor whose absolute value is greater than 1, so our range is [-1,1] and 3 is not part of this range

4 0

3 years ago

Maggie graphed the image of a 90 counterclockwise rotation about vertex A of . Coordinates B and C of are (2, 6) and (4, 3) and

Lemur [1.5K]

Answer:

A(2,2)

Step-by-step explanation:

Let the vertex A has coordinates $(x_A,y_A)$

Vectors AB and AB' are perpendicular, then

$\overrightarrow {AB}=(2-x_A,6-y_A)\\ \\\overrightarrow {AB'}=(-2-x_A,2-y_A)\\ \\\overrightarrow {AB}\perp\overrightarrow {AB'}\Rightarrow \overrightarrow {AB}\cdot \overrightarrow {AB'}=0\Rightarrow (2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0$

Vectors AC and AC' are perpendicular, then

$\overrightarrow {AC}=(4-x_A,3-y_A)\\ \\\overrightarrow {AC'}=(1-x_A,4-y_A)\\ \\\overrightarrow {AC}\perp\overrightarrow {AC'}\Rightarrow \overrightarrow {AC}\cdot \overrightarrow {AC'}=0\Rightarrow (4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0$

Now, solve the system of two equations:

$\left\{\begin{array}{l}(2-x_A)(-2-x_A)+(6-y_A)(2-y_A)=0\\ \\(4-x_A)(1-x_A)+(3-y_A)(4-y_A)=0\end{array}\right.\\ \\\left\{\begin{array}{l}-4-2x_A+2x_A+x_A^2+12-6y_A-2y_A+y^2_A=0\\ \\4-4x_A-x_A+x_A^2+12-3y_A-4y_A+y_A^2=0\end{array}\right.\\ \\\left\{\begin{array}{l}x_A^2+y_A^2-8y_A+8=0\\ \\x_A^2+y_A^2-5x_A-7y_A+16=0\end{array}\right.$

Subtract these two equations:

$5x_A-y_A-8=0\Rightarrow y_A=5x_A-8$

Substitute it into the first equation:

$x_A^2+(5x_A-8)^2-8(5x_A-8)+8=0\\ \\x_A^2+25x_A^2-80x_A+64-40x_A+64+8=0\\ \\26x_A^2-120x_A+136=0\\ \\13x_A^2-60x_A+68=0\\ \\D=(-60)^2-4\cdot 13\cdot 68=3600-3536=64\\ \\x_{A_{1,2}}=\dfrac{60\pm8}{2\cdot 13}=\dfrac{34}{13},2$

Then

$y_{A_{1,2}}=5\cdot \dfrac{34}{13}-8 \text{ or } 5\cdot 2-8\\ \\=\dfrac{66}{13}\text{ or } 2$

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)

8 0

3 years ago