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PIT_PIT [208]
3 years ago
11

Wнaт'ѕ тнe eхpreѕѕιon υѕιng eхponenтѕ м.м.м.p.p.p.p.p.p

Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0
(m*m*m)*(p*p*p*p*p*p) is (m^1*m^1*m^1)*(p^1*p^1*p^1*p^1*p^1*p^1) so what I'm trying to say is m equals 1+1+1 and p equals 1+1+1+1+1+1.
____ [38]3 years ago
5 0
\bf m\cdot m\cdot m\cdot m\cdot p\cdot p\cdot p\cdot p\cdot p\cdot p
\\ \quad \\
m^1\cdot m^1\cdot m^1\cdot m^1\cdot p^1\cdot p^1\cdot p^1\cdot p^1\cdot p^1\cdot p^1
\\ \quad \\
m^{1+1+1}p^{1+1+1+1+1+1}\implies m^{\boxed{?}}p^{\boxed{?}}
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Answer:

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Step-by-step explanation:

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3 years ago
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Mrac [35]

Answer:

x = 6

y = 4

Step-by-step explanation:

Apply the angle bisector theorem to solve for x and y respectively.

✔️4/(9 - x) = 8/x

Cross multiply

4*x = 8(9 - x)

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4 0
3 years ago
Please answer it now
GaryK [48]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
1. When a call is received at an airline’s call center, the probability that it comes from abroad is 0.32, and the probability t
love history [14]

Answer:

a)0.55

b)0.58

Step-by-step explanation:

a) Lets consider that 100 call received from call center. We expect that 32 of them is from abroad and 38 of them is to make a change to an existing reservation. It normally makes that 70 of 100 call is aboard or to make a change. But there are 15 call is in common. Then we need to subtract this number from total calls:

70-15=55 calls we expecting out of 100 calls that both abroad or to make a change.

and the probability is 0.55

b) If we know that they are independent We can use below formula to find in common calls.

P(X=x,Y=y)=P(X=x)P(Y=y)\\P(X=x,Y=y)=0.32*0.38\\P(X=x,Y=y)=0.12

There must be 12 calls in common from out of 100 calls. Now we need to subtract 12 from total calls we expected.

70-12=58 calls we expecting out of 100 calls that both abroad or to make a change.

and the probability is 0.58

8 0
4 years ago
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Aleks [24]

Answer:

speed = distance/ time so:

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8 0
3 years ago
Read 2 more answers
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