3 only
<span>7 only </span>
<span>1 only </span>
<span>1, 4, and 7 </span>
<span>do you mean which digit is added to 371 so that it is divisible by 3 </span>
<span>test for 3, sum of digits divisible by 3 </span>
<span>3 + 7 + 1 = 11 </span>
<span>if you add 3, 11 + 3 = 14 not divisible by 3 </span>
<span>if you add 7, 11+ 7 = 18 divisible by 3 </span>
<span>if you add 1, 11+ 1 = 12 divisible by 3 </span>
<span>if you add 1, 4, 7 divisible by 3 </span>
I = prt
450 = 3000 x r x 3
450 = 9000r
450/9000 = 9000r/9000
r = 0.05
Ok so we know that in ONE second, the dam releases 40000 gallons of water. In ONE minute, there are 60 seconds. Therefore...
1 second----------------40000 gallons
60 seconds--------------? ( this is what we're trying to find.
To get from 1 to 60, we multiplied by 60. Now we do it on the other side. 40000 times 60 is 2,400,000, so the rate in gallons per minute is 2,400,000 gallons per minute
This is the sum of the arithmetic sequence:
10 - 2 + 6 + 14 + ... + 110
where: a 1 = - 10, d = 8
a n = 110
a n = a 1 + ( n - 1 ) * d
110 = - 10 + ( n - 1 ) * 8
110 = - 10 + 8 n - 8
110 + 10 + 8 = 8 n
128 = 8 n
n = 128 : 8
n = 16
∑ n = n/2 * ( a 1 + a n )
∑ 16 = 16/2 * ( -10 + 110 ) = 8 * 100 = 800
Answer:
The sum is 800.
