Using only the digits 5, 6, 7, 8, how many different three digit numbers can be formed if no digit is repeated in a number?

1 answer:

7 0

$4\cdot3\cdot2=24$

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Nitella [24]

l = 2w-3

P = 2(l+w)

substitute in for l

P = 2(2w-3 +w)

combine like terms

P = 2(3w-3)

P = 6w-6

P(w) = 6(w-1)

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2 years ago

liubo4ka [24]

8 x 9 = 72

So 72 is your answer

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2 years ago

Readme [11.4K]

Answer:

$- 3x(x - 4) + 2 - (5 - x) \\ = - 3 {x}^{2} + 12x + 2 - 5 + x \\ = - 3 {x}^{2} + 13x - 3$

I hope I helped you^_^

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2 years ago

scZoUnD [109]

I think b sorry if it’s wrong :(

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2 years ago

Jobisdone [24]

A. -12 is the answer

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3 years ago