If you have a graphing calculator (such as a TI-84), you can use the normalcdf feature by clicking on the blue "2nd" button, then the "vars" button and then choice 2. Since you are finding the proportion of hybrids that get over 61 mpg, the lower bound is 61, the upper bound is infinity (you can type in 99999), the mean is 57, and the standard deviation is 3.5. So... normalcdf(61,99999,57,3.5) = .1265. This means that 12.65% of the hybrids get over 61 mpg.
Answer: B
Explanation:
(75 + 90)/250 = 0.66 = 66% of students are 11 or 12
5/250 = 0.02 = 2% of students are 10
(90 + 70)/250 = 0.64 = 64% of students are 12 or 13
10/250 = 0.04 = 4% of students are 14
Step-by-step explanation:
Answer:
The average score of 6 tests is 19.
Step-by-step explanation:
Given that the average score of 5 tests is 18. So first, we have to find the total number of scores for 5 tests :




We have found out that the total scores for 5 tests is 90. So we have to find the average of 6 scores :

Answer:
The answer to your question is:
Fraction he has review = 17/36
Fraction he have to study = 19/36
Step-by-step explanation:
Data
Monday studied = 2/9
Tuesday = 1/4
Fraction he has review = ?
Fraction he has left = ?
Process
As the denominator is 9, consider the whole is 9.
Then: Fraction left on Monday = 9/9 - 2/9
= 7 / 9
Fraction left on Tuesday = 7/9 - 1/4
= (28 - 9) / 36
= 19 / 36
Fraction he has review = 17/36
Fraction he have to study = 19/36