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Nesterboy [21]
4 years ago
10

Find the sum (3/8x-8)+(3/8x-3)=

Mathematics
1 answer:
love history [14]4 years ago
4 0
The answer is -11, have a good day
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Pablo simplified the expression (2 Superscript negative 4 Baseline) Superscript negative 2 as shown. (2 Superscript negative 4 B
Lorico [155]

Answer:

He should have found 8 as the exponent, not –8.

Step-by-step explanation:

im doing a unit test

8 0
4 years ago
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What is the probability of selecting NUMBER 1?
m_a_m_a [10]

Answer:

there are 10 numbers so it would be 10% but there are 2 ones so 20%

8 0
3 years ago
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At what x value does the function given below have a hole?<br><br> f(x)=x+3/x2−9
S_A_V [24]

Answer:

hole at x=-3

Step-by-step explanation:

The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)

The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.

So anyways we have (x+3)/(x^2-9)

= (x+3)/((x-3)(x+3))

Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.

4 0
3 years ago
A restaurant gets an average of 12 phone orders in a 2 hour time period. In order to find the probability that the restaurant wi
Roman55 [17]

Answer:

The average number of phone calls in a 30 minute period is 3.

The probability to receive exactly 2 calls in that period is 0.224.

Step-by-step explanation:

If we are using the same Poisson distribution in the 2 hour period, then the average of phone orders in a reduced interval will be reduced according to that interval. Since 30 minutes is four times smaller than 2 hours, then the average number of phone orders per 30 minutes is 12 * 1/4 = 3. This can also be computed with a Rule of 3

120 minutes -------------> 12 orders

30 minutes ---------------> X orders

X = 30*12/120 = 3

Lets call Y the amount of phone orders received during a specific (random) 30 minute period. Since the average was 3, then Y has a Poisson distribution with parameter 3. The probability of Y being equal to 2 is

P(Y=2) = \frac{e^{-3} 3^2 }{2!} = \frac{9}{2} \, e^{-3} = 0.224

Thus, the probability to receive exactly 2 calls in a 30 minute period is 0.224.

4 0
4 years ago
Out of 1,400 students, 60% have a dog. How many students have a dog in part ?
Stells [14]

Answer:

840 students

Step-by-step explanation:

0.6 * 1400 = 840 students

8 0
3 years ago
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