PLEASS HELPP!!!!!!! PICTURE SHOWN

Graphing using the y intercept and slope: y = - 3x + 5 b(y - intercept) = m(slope) =

babymother [125]

The answer is 3x- I just took the text

6 0

2 years ago

Y= 1/2x -3 on a graph<br> I’m confused on how to graph 1/2x - 3

amid [387]

Answer:

Put your equation into this!

Step-by-step explanation:

desmos.com/calculator

It will graph it for you!

You are very welcome!!

3 0

3 years ago

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Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, $b$ must be a natural number, which means that:

$1 + 2\cdot a\cdot c \ge 4$

$2\cdot a \cdot c \ge 3$

$a\cdot c \ge \frac{3}{2}$

But the lowest possible product made by two prime numbers is $2^{2} = 4$ . Hence, $a\cdot c \ge 4$ .

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Example: $a = 2$ , $c = 2$

$b = \sqrt{1 + 2\cdot (2)\cdot (2)}$

$b = 3$

4 0

2 years ago

PLEASE HELP ME!!! IM STRUGGLING

kakasveta [241]

A is 0.

B is 7.

C. is 3.

D is 0.

I dont know E.

F is 3.

G is 0.

8 0

2 years ago

Select the expression that represents the simplified difference.

Setler79 [48]

The simplified expression for the given function is 2x + 4 - ( 1 / x-1). The correct option is A.

<h3>What is an expression?</h3>

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the functions are f(x) = x + 2 and h(x) = 1 / x-1. The value of the function 2f(x) – h(x) will be calculated as,

E = 2f(x) – h(x)

E = 2( x + 2 ) - ( 1 / x-1)

E = 2x + 4 - (1/x-1)

To know more about an expression follow

brainly.com/question/29008655

#SPJ2

8 0

1 year ago

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