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Vsevolod [243]
3 years ago
15

Please help me with this radical expression​

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

a. ⁴√x³

d. ¹²√x⁹

Step-by-step explanation:

First, simplify 9⁄12 to ¾. Then, according to the Definition of Rational Exponents [part II], ⁿ√aᵐ = aᵐ\ⁿ, you set your denominator equal to the root, and your numerator becomes your exponent, keeping your base INSIDE the radical.

I am joyous to assist you anytime.

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The parent function of the logarithm is f(x) =log x. if g(x) = log(x-4)-3 write down the transformation
Aliun [14]

Answer:

Step-by-step explanation:

The (x - 4) indicates side-to-side movement, and the -3 at the end indicates up and down movement.  This log graph has moved 4 units to the right (x - (4)) and down 3 units (-3)

5 0
3 years ago
Suppose someone tells you that she has a triangle with sides having lengths 2.6, 8.1, and 8.6. Is this a right triangle? Why or
Elodia [21]
First you check for Pythagoras'  Theorem.

Is  8.6² = 8.1²  + 2.6²  ? 
  
8.1²  + 2.6² = 65.61 + 6.76 = 72.37
8.6² =  73.96

8.1²  + 2.6²  ≠ 8.6² 

Since Pythagoras' Theorem is not satisfied it is not a right angled triangle.

The longest side is 8.6,  let's find the angle facing the longest side 8.6.

By cosine formula  CosA =  (b² + c² - a²) / (2bc)

CosA =  (2.6² + 8.1² - 8.6²) / (2*2.6*8.1) = -1.59/42.12 = -0.0377

A = Cos inverse (-0.0377) = 92.1 degrees

So there is  an angle is greater than 90 degrees.
8 0
3 years ago
15 / √31 - 4
NeX [460]

Answer:

\frac{15}{ \sqrt{31} - 4}} = \sqrt{31} + 4

Step-by-step explanation:

\frac{15}{\sqrt{31} - 4}\\\\=\frac{15}{\sqrt{31} - 4} \times \frac{\sqrt{31} + 4}{\sqrt{31}+ 4} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   [  \ rationalizing \ the \ denominator \ ]\\\\=\frac{15( \sqrt{31} + 4 )}{(\sqrt{31})^2 - (4)^2}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ [ \ (a-b)(a+b) = a^2 - b^2 \ ]\\\\=\frac{15 ( \sqrt{31} + 4)}{31 - 16}\\\\=\frac{15 (\sqrt{31} + 4)}{15}\\\\= \sqrt{31} + 4

6 0
3 years ago
Show all work to factor x^4 − 17x^2 + 16 completely.
Dmitrij [34]

Answer:

x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

Step-by-step explanation:

At first, let us find the first two factors of x^{4}-17x^{2} +16

∵ The sign of the last term is positive

∴ The middle signs of the two factors are the same

∵ The sign of the middle term is negative

∴ The middle signs of the two factors are negative

∵ x^{4} = x² × x² ⇒ first terms of the two factors

∵ 16 = -1 × -16 ⇒ second terms of the two factors

∵ x²(-1) + x²(-16) = -x² + -16x² = -17x² ⇒ the value of the middle term

∴ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

Now let us factorize each factor

→ The factors of the binomial a² - b² (difference of two squares) are

   (a - b) and (a + b)

∵ x² - 1 is the difference of two squares

∴ Its factors are (x - 1) and (x + 1)

∵ x² - 16 is the difference of two squares

∴ Its factors are (x - 4) and (x + 4)

∵ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of (x² - 1) and (x² - 16)

∵ (x² - 1) and (x² - 16) are the factors of x^{4}-17x^{2} +16

∴ (x -1), (x + 1), (x - 4), and (x + 4) are the factors of x^{4}-17x^{2} +16

∴  x^{4}-17x^{2} +16 = (x -1)(x + 1)(x - 4)(x + 4)

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