Yes they can be used in a triangle the sides: AB, BC, AC Angles: Angle C, Angle A, Angle B.
Add the two equations:
2x + 4y = 16
-2x - 3y = -6
2x + -2x = 0
4y -3y = y
16-6 = 10
When you add the equations you get y = 10
Now you have a value for y, use the first equation to solve for x:
2x + 4(10) = 16
2x + 40 = 16
Subtract 40 from both sides:
2x = -24
Divide both sides by 2
X = -12
Answer: x = -12 and y = 10
The total if all 236 coins were nickels would be $11.80, which is $3.95 short of the actual amount.
Replacing a nickel with a dime adds $0.05 to the total value, so there must have been $3.95/$0.05 = 79 such replacements.
There are 79 dimes.
There are 236 -79 = 157 nickels.
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Using the given variables, the problem statement gives rise to two equations. One is the based on the number of coins. The other is based on their value.
- n + d = 236
- .05n +.10d = 15.75
Solving the first for n, we get
... n = 236 - d
Substituting that into the second equation, we have
... .05(236 -d) +.10d = 15.75
... .05d = 15.75 -236·.05 . . . . . collect terms, subtract .05·236
... d = 3.95/.05 . . . . . . . . . . . . . divide by .05
... d = 79
... n = 236-79 = 157
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The solution should look familiar, as it matches the verbal description at the beginning.
You are strange if u like blondies. PERIOD!
Step-by-step explanation:
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