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3 years ago

15

There are 4 quarters in 1 dollar. The total number of dollars is a function of the number of quarters. Does this situation repre

sent a linear or nonlinear function?

1 answer:

Kay [80]3 years ago

3 0

Linear because the slope will always be the same

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What’s the area?? There’s a picture

Montano1993 [528]

Answer:

A= 12 Ft^2

Step-by-step explanation:

Reminder the Area formula is A=B(Base) times H(Height).

Take The base (6) and the Height (6) then multiply.

Hence, the reason is 12 Ft squared.

6 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min, and its coarseness is such that it forms a pile in the shap

ikadub [295]

The height is increasing at the rate of (6/5π) ft/min.

It is given that Gravel is being dumped from a conveyor belt at a rate of 40 ft3/min. Also, its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal.

For this, we need to find the volume of a cone. Volume is a scalar quantity expressing the amount of three-dimensional space enclosed by a closed surface.

The volume of a cone is - V=1/3hπr²

Learn more about integers here: brainly.com/question/20521181

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4 0

2 years ago

How do you write an equation to represent a real-world situation?

Maurinko [17]

You have to organize the parameters of the real-world situation that is known and unknown. Also, you have to distinguish which of them are dependent and independent. Next, you assign letters as your variables. Lastly, you make an algebraic expression by translating the relationship into the mathematics.

4 0

4 years ago

Milo pays $3 per pound for dog food at Pat’s Pet Palace. The graph below represents the cost per pound of food at Mark’s Mutt Ma

Neko [114]

Where’s the graph ? I think you’ll need to show the graph in order for us to help you

4 0

3 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

7 0

3 years ago