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3 years ago

How many solution does each graph have

Mathematics

1 answer:

SVEN [57.7K]3 years ago

4 0

Answer:

one solution 

no solution 

infinity solutions 

Step-by-step explanation:

A: If the graphs of the equations intersect, then there is one solution that is true for both equations.

B; If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations.

C; If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations

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snow_tiger [21]

Answer:

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3 years ago

GaryK [48]

Answer:

$B_2=4\pi r^2$

see the explanation

Step-by-step explanation:

we know that

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where

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If the radius is doubled

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3 years ago

Which statement is true?

Elis [28]

Answer: Last option is true,

Step-by-step explanation: All other option are false

8 0

2 years ago

the length of a tangent from a point a at distance 5 cm from the centre of the circle is 4 cm find the radius of the circle

Semenov [28]

The radius of the circle is 3 cm.

Step-by-step explanation:

Refer the attached diagram, the circle with centre O. In that given, AB is tangent given as 4 cm and distance of point from the circle, OA = 5 cm

As AB is tangent, OB (radius of circle) is perpendicular to AB (tangent at any point of circle). Therefore the angle of OBA is 90 degree.

Also, triangle OAB is a right angled triangle (refer attached diagram). By using Pythagoras theorem in right angled triangle,

$(\text {Hypotenuse})^{2}=(\text {Height})^{2}+(\text {Base})^{2}$

$(O A)^{2}=(O B)^{2}+(A B)^{2}$

Substitute the given values in the above expression, we get

$(5)^{2}=(O B)^{2}+(4)^{2}$

$(O B)^{2}=25-16=9$

Taking square root on both side, we get

Radius of the circle, OB = 3 cm

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3 years ago

Twelve and twenty nine hundredths in number form

kobusy [5.1K]

Answer:

12.29

Step-by-step explanation:

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3 years ago

Read 2 more answers