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eduard
4 years ago
10

Duane is making cookies. The recipe calls for two times as many cups of sugar as butter, two times as many cups of oats as sugar

, and two times as many cups of flour as oats. If Duane puts in one cup of butter, how many cups of flour does he need to add?​
Mathematics
1 answer:
Tamiku [17]4 years ago
6 0

Answer:

6.0

Step-by-step explanation:

: (2.0+(2.0+2.0)) = 6.0

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0.2cubed + (1/5 * 3/4) - 1/12
solmaris [256]

Answer:

Step-by-step explanation:

0.2³ + (1/5 × 3/4) - 1/12

According to my syllabus, we use BODMAS. i.e <em>Brackets, Of, Division, Multiplication, Addition </em>and <em>Subtraction</em> in that order.

0.2³ +  3/20 - 1/12

0.008 + 3/20 - 1/ 12

Change the decimal to a fraction and work out the rest.

6 0
3 years ago
I)x-1 by 4=3<br>ii)3x+6 by 2=3 by 2<br>iii)3x-1by5=2x+3by7​​
suter [353]

Answer:

13,-1,2

Step-by-step explanation:

i hope it is helpful......for you

3 0
3 years ago
It seems to you that fewer than half of people who are registered voters in the City of Madison do in fact vote when there is an
Ad libitum [116K]

Answer:

a) Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

b) The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

c) We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

d) The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

(a) How might a simple random sample have been gathered?

Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

(b) Construct an 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

You take an SRS of 200 registered voters in the City of Madison, and discover that 122 of them voted in the last non-presidential election. This means that n = 200, \pi = \frac{122}{200} = 0.61.

We want to build an 80% CI, so \alpha = 0.20, z is the value of Z that has a pvalue of 1 - \frac{0.20}{2} = 0.90[tex], so [tex]z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 - 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.5533

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 + 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.6667

The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

(c) Interpret the interval you created in part (b).

We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

(d) Based on your CI, does it seem that fewer than half of registered voters in the City of Madison vote in non-presidential elections? Explain.

The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

4 0
3 years ago
Find an order pair (x, y) that is a solution to the equation <br> -x+6y=3
Lelu [443]
One solution is the y intercept (0,1/2)
3 0
3 years ago
If abc avw find the values of x and y
zavuch27 [327]

Answer:

x=7.2 y=7.5 this is the answer

8 0
3 years ago
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