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bulgar [2K]
3 years ago
11

Consider the element in the periodic table as we move to the far right Greg column on the far right is made up of

Mathematics
2 answers:
Novay_Z [31]3 years ago
7 0

Answer:

As we move to the far right, the purple column is made up of gases that are. The purple column represents noble gases.

Step-by-step explanation:

Afina-wow [57]3 years ago
6 0

Answer:Elements on the right side of the periodic table are NONMETALS. The staggered stair step on the periodic table divides the metals from the nonmetals. Metalloids are located on the stair step.

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Pink floyd had a song named brain damage true or false
marusya05 [52]

Answer:

True

Step-by-step explanation:

4 0
3 years ago
WILL GIVE BRAINLIEST!
Radda [10]

Answer:

4 ounces of corn and 4 ounces of squash

Step-by-step explanation:

Let S be the no. of ounces of squash

Let C be the no. of ounces of corn

C》2 --> (A)

S》C --> (B)

Total protein 》 3

½C + ¼S》3 --> (C)

Solve A and C simultaneously

½(2) + ¼S = 3

¼S = 2

S = 8

C = 2, S = 8

Solve B and C simultaneously

½S + ¼S = 3

¾S = 3

S = 4

C = 4, S = 4

Three possible extreme combinations

C = 2, S = 8: Total = 10

C = 4, S = 4: Total = 8

Minimum is 8 ounces

4 0
2 years ago
Value of this problem?
Rudik [331]
\frac{4^3\times4^{-1}\times5^{-2}}{4^4\times5^{-3}\times5^0}=\frac{4^{3-1}\times5^{-2}}{4^4\times5^{-3+0}}\\=\frac{4^{2}\times5^{-2}}{4^4\times5^{-3}}=4^{2-4}\times5^{-2-(-3)}\\=4^{-2}\times5^{1}=\frac{5}{4^2}\\=\frac{5}{16}
5 0
2 years ago
Please help asap!! I need help
lana66690 [7]
It would be -5 because 4- 3*12/4 = -5

Hope this helps

Have a great day/night
4 0
3 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
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