Question

What is the solution of the system of equations?

Answer 1

$\left\{\begin{array}{ccc}72x-12y=92&|:12\\3x-y=5\end{array}\right\\\left\{\begin{array}{ccc}6x-y=\dfrac{23}{3}&|\cdot(-1)\\3x-y=5\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-6x+y=-\dfrac{23}{3}\\3x-y=\dfrac{15}{3}\end{array}\right}\ \ \ |\text{add both sides of equations}\\.\ \ \ \ \ \ -3x=-\dfrac{8}{3}\ \ \ \ |:(-3)\\\\.\ \ \ \ \ x=\dfrac{8}{9}$

$\text{put the value of x to the first equation}\\\\-6\left(\dfrac{8}{9}\right)+y=-\dfrac{23}{3}\\\\-2\cdot\dfrac{8}{3}+y=-\dfrac{23}{3}\ \ \ |\cdot3\\\\-16+3y=-23\ \ \ |+16\\\\3y=-7\ \ \ |:3\\\\y=-\dfrac{7}{3}\\\\\text{Answer:}\ x=\dfrac{8}{9},\ y=-\dfrac{7}{3}$

Answer 2

Answer:

(1,-2)

Step-by-step explanation:

just took the test and it said this was the answer