Little help here please.
1 answer:
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Answer:
Step-by-step explanation:
a) H0:
Ha:
(Two tailed test at 5% significance level)
b) n=30
Mean difference =
Std error of mean =
b) Test statistic t = mean diff/std error = -1.552
df = 30-1 =29
p value=0.0657
c) Since p > 0.05 our signi. level, we accept null hypothesis.
There is no significant difference between the means.
d) Using critical value we find that test statistic is > critical value left
So accept H0