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Naddika [18.5K]

3 years ago

6

What is the value ofcos pie value

1 answer:

Hitman42 [59]3 years ago

3 0

Cos(pi) = -1

You should have this memorized along with other values such as
sin(0) = 0
cos(0) = 1
sin(pi/2) = 1
cos(pi/2) = 0
sin(pi) = 0
cos(pi) = -1
sin(3pi/2) = -1
cos(3pi/2) = 0

and remember that tan = sin/cos

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Two congruent squares and a parallelogram were used to form the figure shown. 3 meters, 6 meters, 2.8 meters, 3 meters What is t

elixir [45]

The area of a figure is the amount of space the figure occupies

The surface area of the figure is 34.8 square meters

<h3>How to determine the area of the shape</h3>

From the question, we have:

The dimensions of the congruent squares are 3 m by 3 m
The dimensions of the parallelogram are height of 2.8 m, and base of 6 m

So, the area of the figure is:

Area = 2 * Area of square + Area of parallelogram

This gives

$Area = 2 * (3m * 3m) + 2.8m * 6m$

Evaluate the products

$Area = 18m^2 + 16.8m^2$

Evaluate the sum

$Area = 34.8m^2$

Hence, the surface area of the figure is 34.8 square meters

Read more about surface areas at:

brainly.com/question/24571594

3 0

2 years ago

2900 dollars is placed in an account with an annual interest rate of 9% Wirte an equation that calculates how many dollars will

valentinak56 [21]

Answer:

The amount that will be in the account will be $(2900 +261x)

Step-by-step explanation:

We know that the amount of money that will be in the account will be a sum of the initial principal ($2900) and the interest that is accrued after x years.

Since we already know the principal, we will have to calculate the interest that is accrued after x years.

we can use the formula:

Interest = (principal X rate X time)/ 100

Interest = $(2900 \times 9 \times x)/100=261x$

Therefore the amount that will be in the account will be $(2900 +261x)

6 0

3 years ago

Which of the following is a quadratic function in standard form?

Veseljchak [2.6K]

Answer:

A.

Step-by-step explanation:

Standard form is as follows...

AX^2 + BX + C

- Hope that helped! Please let me know if you need further explanation.

6 0

4 years ago

Read 2 more answers

The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to

jarptica [38.1K]

Answer:

The width = x = 14

The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

$x^2-11x=42$

$\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2$

$x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}$

$\left(x-\frac{11}{2}\right)^2=\frac{289}{4}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{11}{2}=\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{2}$

$x-\frac{11}{2}=\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}$

$x=14$

similarly solving

$x-\frac{11}{2}=-\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=-\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}$

$x=-3$

so

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

The width = x = 14

The length = x+5 = 14+5 = 19

6 0

3 years ago

There are 104 students in fourth grade at Allison’s school.One day, 15 fourth graders were absent. How many fourth graders were

stich3 [128]

Answer: 89 students remained at school that day.

Step-by-step explanation: If there are 104 students, and 15 are absent, you subtract, therefore, the answer is 89.

3 0

3 years ago

Read 2 more answers