Answer: Choice B) {3, 5, sqrt(34)}
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Explanation:
We can only have a right triangle if and only if a^2+b^2 = c^2 is a true equation. The 'c' is the longest side, aka hypotenuse. The legs 'a' and 'b' can be in any order you want.
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For choice A,
a = 2
b = 3
c = sqrt(10)
So,
a^2+b^2 = 2^2+3^2 = 4+9 = 13
but
c^2 = (sqrt(10))^2 = 10
which is not equal to 13 from above. Cross choice A off the list.
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Checking choice B
a = 3
b = 5
c = sqrt(34)
Square each equation
a^2 = 3^2 = 9
b^2 = 5^2 = 25
c^2 = (sqrt(34))^2 = 34
We can see that
a^2+b^2 = 9+25 = 34
which is exactly equal to c^2 above. This confirms the answer.
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Let's check choice C
a = 5, b = 8, c = 12
a^2 = 25, b^2 = 64, c^2 = 144
So,
a^2+b^2 = c^2
25+64 = 144
89 = 144
which is a false equation allowing us to cross choice C off the list.
Answer:
45
Step-by-step explanation:
Since the values are relatively small substitute i = 1 to 5 into 3i and sum
(3 × 1) + (3 × 2) + (3 × 3) + (3 × 4) + (3 × 5)
= 3 + 6 + 9 + 12 + 15
= 45
It’s 100°! I cause 75+75 = 150 and if the circle is 350 then 150-350 = 200 and 200÷2 is 100
I think answer is A
Because slope=rise/run
Rise is 3
Run is 2
But it will be negative because of the direction of slope
