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FrozenT [24]
3 years ago
15

Find the value of x if Sin80 = Cos( 90 -x)

Mathematics
1 answer:
natita [175]3 years ago
5 0

Answer:

80

Step-by-step explanation:

\sin(80)  =  \cos(10)  \\ 90 - x = 10 \\ x = 80

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What's the slope of the graph
kotykmax [81]

Answer:

1/-2

Step-by-step explanation:

To find the slope:

rise/run

From point to point

So....

From (-1,0)

you go up 2(2)

then left 4(-4)

to get to (-5,2)

so 2/-4 reduced is 1/-2

6 0
3 years ago
What is 2^4+5*6*4+4/2*50 plz help
Lelechka [254]

It is 236. Happy to help (:

6 0
3 years ago
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If two 12-sided dice are rolled, what is the probability that both numbers will be even?
geniusboy [140]
1/4 I think, I’m not sure
7 0
3 years ago
What are the transformations to this quadratic function y= (x+4) power of 2 - 8
I am Lyosha [343]

Answer:

Horizontal shift of 4 units to the left.

Vertical translation of 8 units downward.  

Step-by-step explanation:

Given the quadratic function, y = (x + 4)² - 8, which represents the horizontal and vertical translations of the parent graph, y = x²:

The vertex form of the quadratic function is y = a(x - h)² + k

Where:

The vertex is (h , k), which is either the <u>minimum</u> (upward facing graph) or <u>maximum</u> (downward-facing graph).

The axis of symmetry occurs at <em>x = h</em>.

<em>a</em> =  determines whether the graph opens up or down, and makes the graph wider or narrower.

<em>h</em> = determines how far left or right the parent function is translated.

<em>k</em> = determines how far up or down the parent function is translated.

Going back to your quadratic function,

          y = (x + 4)² - 8

  • The vertex occrs at (-4, -8)
  • a is assumed to have a value of 1.
  • Given the value of <em>h</em> = -4, then it means that the graph shifted horizontally by <u>4 units to the left</u>.  
  • Since k = -8, then it implies that the graph translated vertically at <u>8 units downward</u>.

Please mark my answers as the Brainliest, if you find this helpful :)

4 0
2 years ago
Let f (x) = 3x − 1 and ε &gt; 0. Find a δ &gt; 0 such that 0 &lt; ∣x − 5∣ &lt; δ implies ∣f (x) − 14∣ &lt; ε. (Find the largest
s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and \varepsilon>0, we want to find a \delta such that |f(x)-14|

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that |x-5|. Then

|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta.

Then, if |x-5|, then |f(x)-14|. So, in this case, if 3\delta \leq \varepsilon we get that |f(x)-14|. The maximum value of delta is \frac{\varepsilon}{3}.

By definition, this procedure proves that \lim_{x\to 5}f(x) = 14. Note that f(5)=14, so this proves that f is continous at x=5.

3 0
3 years ago
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