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stiks02 [169]
4 years ago
14

How do you find rate of change using a graph?

Mathematics
2 answers:
worty [1.4K]4 years ago
8 0

Answer:

Look at one point and then go over and down and over would be the top and the down would be the bottom number

Step-by-step explanation:

Ber [7]4 years ago
3 0

U find the rate of change by using the equation:

Y^2-y^1

————-

X^2-x^1

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5.6+ 2.2x> 65.6- 1.8x show you work
11Alexandr11 [23.1K]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form: x>15

Interval Notation:(15,∞)

Step-by-step explanation:

Hope this helps   ;)

7 0
3 years ago
What is the answer of the ratio 63:27
Darina [25.2K]

Answer is; 7/3, which is 2 and 1/3 or you can say 2,333.....

Why?

63/27=7*9/3*9 ; {removing 9 from both gives 7/3}

3 0
3 years ago
Read 2 more answers
For the function f(x) = x + 7, what is the ordered pair for the point on the graph when x = 2b? (2b, 2b + 7) (2b, x + 7) (x, x +
Ostrovityanka [42]

Answer:

(2b, 2b + 7)

Step-by-step explanation:

y=f(x) = x +7

x= 2b

y=f(2b) = 2b +7

(2b, 2b + 7)

6 0
3 years ago
Read 2 more answers
¿Cuántas cifras tiene el número quinientos cincuenta y cinco mil? Respuesta: ____________ CM DM UM C D U NÚM. DE CIFRAS
Burka [1]

Answer:

6 cifras.

Step-by-step explanation:

Siempre que tengamos un numero que termina en "mil", entonces la primer parte la escribimos y luego ira una coma:

por ejemplo, en "ciento once mil trecientos catorce"

lo separamos en:

"ciento once mil" y "trecientos catorce"

y lo escribimos como:

"ciento once" , "trecientos catorce"

111,314

Ahora que definimos esto, vamos a nuestro problema.

Tenemos el numero "quinientos cincuenta y cinco mil"

El cual podemos escribir como:

555,000

Ahora simplemente podemos contar las cifras, tenemos 6.

las cuales son:

Cientos de miles = CM = 5

Decenas de miles = DM = 5

Un miles = UM = 5

Cientos = C = 0

Decenas = D = 0

Unidades = U = 0

4 0
3 years ago
A coffee shop plans to blend a coffee that sells for $12 per pound with coffee that sells for $9 per pound to produce a blend th
zvonat [6]

Answer:

20/3 pounds of coffee that costs $12 per pound  and 40/3 pounds  of coffee that costs $9 per pound are required

Step-by-step explanation:

Let x be the amount of coffee that costs $12 per pound

Cost of x amount of this type coffee = 12x

We are supposed to find How much of each should be used to produce 20 pounds of the new blend that costs $10 per pound

So, Amount of coffee required that costs $9 per pound = 20-x

Cost of (20-x) amount of this type of coffee = 9(20-x)

So, 12x+9(20-x)=10(20)\\12x+180-9x=200\\3x=20\\x=\frac{20}{3}

Amount of coffee that costs $12 per pound required is\frac{20}{3} pounds

Amount of coffee that costs $9 per pound required = 20-x=20-\frac{20}{3}=\frac{40}{3} pounds

Hence 20/3 pounds of coffee that costs $12 per pound  and 40/3 pounds  of coffee that costs $9 per pound are required

8 0
4 years ago
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