Question

A line contains points M(1, 3) and N(5, 0). What is the slope of MN? negative StartFraction 4 Over 3 EndFraction negative StartFraction 3 Over 4 EndFraction StartFraction 3 Over 4 EndFraction StartFraction 4 Over 3 EndFraction

Answer 1

Answer:

The slope would be -3/4

Step-by-step explanation:

Since, slope of a line having end points $(x_1, y_1)$ and $(x_2, y_2)$ is,

$m=\frac{y_2-y_1}{x_2-x_1}$

Here, line segment MN contains end points M(1, 3) and N(5, 0)

i.e.

$x_1 = 1, y_1 = 3, x_2 = 5, y_2 = 0$

Thus, the slope of line MN would be,

$m=\frac{0-3}{5-1}=\frac{-3}{4}$

Answer 2

(x1,x2), (y1,y2)

(1,3), (5,0)

0-3/5-1

-3/4