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SOVA2 [1]
3 years ago
7

Write 5.19 x 10^2 in standard form.

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

519

hope this helped you

:)

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What is the slope of the line that passes through the given points? (1,8) (8,9)
igor_vitrenko [27]
9-8        1
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The answer is 1/7.
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Complete a table with at least 5 points then graph the following quadratic on the coordinate plane. Identify all zeros.y = -2x2
Anna [14]

Answer:

See attached

Step-by-step explanation:

Given function:

  • y = -2x² + 5x + 8

Table and graph are attached

Zeros are included in the graph

<u>Zero's are obtained:</u>

x = 0 ⇒ y = 8

y = 0 ⇒  Solving quadratic equation

  • -2x² + 5x + 8 = 0
  • x = (-5 ± √(25 + 2*4*8))/-4
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  • x = -1.108

So zeros are (0, 8), (3.608, 0) and (-1.108, 0)

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4 years ago
4125 x 10 to the 3rd power
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In standard form, it would look like this:

4125 * 1000

This would be 4,125,000

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3 years ago
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3 years ago
Please can some explain how to identify angles that on the same segment? ​
sp2606 [1]

Step-by-step explanation:

Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.

Picture 1  a° = a°  they are the same

Picture 2  p= 52°  q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.

Picture 3 + 4  Let the obtuse angle MOQ = 2x.  

Using the circle theorem, the angle at the centre is twice   the angle at the circumference.

Therefore picture 4 tells us and proves;

Angle MNQ = x and angle MPQ = x.

Picture 5

A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.

The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.

Picture 6

The opposite angles in a cyclic quadrilateral add up to 180°.

a + c = 180°

b + d = 180°

Picture 7

Example

Calculate the angles a and b.

The opposite angles in a cyclic quadrilateral add up to 180°.

This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °

So hopefully this will help you remember the format here for quadrilateral shapes within a circle.

b = 180 - 140 = 40°

a = 180 - 60 = 120°

8 0
3 years ago
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