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AnnZ [28]
3 years ago
15

This circle and x + 2y= 12 create a system of equations.

Mathematics
1 answer:
NISA [10]3 years ago
6 0

There's something wrong with the answer choices.

There are 2 solutions because the line x+2y = 12 and the circle intersect at two locations. One point of intersection is (0,6). So this suggests choice B is the answer; however, the point (12,0) is not a solution.

It works for x+2y = 12 since 12+2(0) = 12. But the point (12,0) is not on the circle. The furthest to the right we go is (6,0).

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The midpoint of segment AB is (-7, 10) and endpoint A is located at (3, -1). Find the other endpoint B. Show all work.
dusya [7]

Answer:

B(-17,21)

Step-by-step explanation:

The midpoint of two points is the average of the x coordinates and the average of the y coordinates.

Given

A(3, -1)

and we let the other end point B be B(x,y)

and midpoint is (-7,10)

So, the average of 3 and x is -7, and

the average of -1 and y is 10

We can solve for x first:

\frac{3+x}{2}=-7\\3+x=2*-7\\3+x=-14\\x=-14-3\\x=-17

and now solving for y:

\frac{-1+y}{2}=10\\-1+y=2*10\\-1+y=20\\y=20+1\\y=21

So, the other point B is:

B(-17,21)

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3 years ago
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Solve for p. 2(p + 1) = 16 What is the answer?
Mashutka [201]

Divide both sides by 2

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4 0
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Read 2 more answers
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olga_2 [115]

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25

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