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Yakvenalex [24]
2 years ago
10

Help please.! and thank you

Mathematics
1 answer:
Alexxx [7]2 years ago
8 0

Answer:

common difference is 4

Step-by-step explanation:

12-4=8

8-4=4

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What is the 28th term?
adelina 88 [10]
The answer would be -112.
You are adding -4 to the previous term so all you have to do is...
28x4 the put the negative sign so the answer -112
3 0
3 years ago
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581/1000 in simplest form?
elena-s [515]
Hello
Your answer is
0.581
And remember,any number divided by 10,100,1000 and its smaller it will be the same number,but in decimal form
Good luck!
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A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
If x+3 is a factor of x^3-x^2-10x+A. What is the value of A?
Leno4ka [110]

Answer:

A = 6.

Step-by-step explanation:

Let a denote a constant (a number, rather than a variable like x.)

Let f(x) denote an expression about x (for example,

By the factor theorem, if (x - a) is a factor of f(x), then f(a) = 0. In other words, if all mentions of x in the expression f(x)\! are replaced with a, then the expression should evaluate to zero.

(x + 3) is equivalent to (x - (-3)). That is: a = -3.

Replace all mentions of x in x^3 - x^2 - 10\, x + A by (-3) to get:

(-3)^3 - (-3)^2 - 10\times (-3) + A.

That should evaluate to zero. Therefore: -27 - 9 + 30 + A = 0. Solve for A to get A = 6.

7 0
3 years ago
Find the equation of a line that passes through the point (4,2) that is perpendicular to the line y=4/3 x
Mrac [35]

Answer:

y=\frac{3}{4}x-1

Step-by-step explanation:

Since we're looking at perpendicular lines, the slope of the new line is the reciprocal of the original line.

So the slope of our new line is \frac{3}{4}

So far, we are looking at y=\frac{3}{4} x+b

Now we need to find the b value by plugging in the given point.

2=\frac{3}{4}(4)+b\\  2=3+b\\ b=-1

So the final equation is y=\frac{3}{4}x-1

8 0
3 years ago
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