All categories

3 years ago

Which line has a slope of 1 and a y-intercept of 2?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

Answer:

bottom left :)

Step-by-step explanation:

You might be interested in

How do you determine the number of zeros to Annex in the product of 0.002 + 0.003

lorasvet [3.4K]

2*10^-3 + 3*10^-3
(2+3)*10^-3
5*10^-3
since the sum of coefficients of the 10^-3 are less than 10, we still have the same number of zeros
0.005

3 0

3 years ago

What is the simplified value of this expression pls help

tester [92]

Answer:

Step-by-step explanation:

Remove parentheses.

$\frac{-8+4(4.5)}{6.25-8.25} \\$

Add −8 and 4.5.

$\frac{4(-3.5)}{6.25 - 8.25} \\\\$

Subtract 8.25 from 6.25.

$\frac{4*-3.5}{-2}$

Multiply 4 by −3.5.

$\frac{-14}{-2}$

Divide −14 by −2.

= 7

7 0

3 years ago

1. A sample is being chosen for a survey to find out how people feel about adding more stop signs near a school. Which group wou

Anna71 [15]

I think that it would be voters because they are asking the people if they should or not.

8 0

3 years ago

Help asap pls 15 points

Alinara [238K]

Answer:

1. 20 by 6

2. 20 by 8

3. 6 by 10

4. 6 by 40

Step-by-step explanation:

just do 2/3 of each number then that is the new number.

1/3 of 30 is 10, so 2/3 is 20.

and so on

4 0

2 years ago

What two numbers can add to 4 but multiple to -12

olasank [31]

Answer:

<em>Numbers: 6 and -2</em>

Step-by-step explanation:

<u>Equations</u>

This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.

However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:

$x+y=4\qquad\qquad [1]$

$x.y=-12\qquad\qquad [2]$

Solving [1] for y:

$y=4-x$

Substituting in [2]

$x(4-x)=-12$

Operating:

$4x-x^2=-12$

Rearranging:

$x^2-4x-12=0$

Solving with the quadratic formula:

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

With a=1, b=-4, c=-12:

$\displaystyle x=\frac{-(-4)\pm \sqrt{(-4)^2-4(1)(-12)}}{2(1)}$

$\displaystyle x=\frac{4\pm \sqrt{16+48}}{2}$

$\displaystyle x=\frac{4\pm 8}{2}$

The solutions are:

$\displaystyle x=\frac{4+ 8}{2}=6$

$\displaystyle x=\frac{4- 8}{2}=-2$

This confirms the preliminary results.

Numbers: 6 and -2

7 0

3 years ago