In addition to age, the gomez score was originally based on the measurements of:

What is the slope intercept form of y + 1 = -2 (x-1)?

Mars2501 [29]

Y+1 = -2x+2 (distribute)
Y=-2x + 1 (isolate y)

4 0

3 years ago

Read 2 more answers

Help what are the answers im so stuck!

AnnZ [28]

Answer:

see below

Step-by-step explanation:

A percentage change is computed as follows:

percent change = ((new value) -(original value))/(original value) × 100%

For your first one, this looks like ...

percent change = ($25 -$75)/$75 × 100% = (-50/75) × 100% = -0.667×100%

percent change = -66.7%

__

When there are a lot of similar calculations to do, I like to use a spreadsheet. See below for the other percentage changes (rightmost column).

4 0

3 years ago

PLZ HELP ME! Whoever gets it right will be marked brainiest

Brut [27]

Answer:

Probability that Hannah only has to buy 3 or less boxes before getting a prize is 0.784

Step-by-step explanation:

Given, 40% of cereal boxes contain a prize

⇒probability of getting a prize on opening a box, P(A)=0.4

where A is the event of getting a prize on opening a cereal box

and probability of not getting a prize on opening a box, P(A')=1-P(A)=0.6

where A' is the event of not getting a prize on opening a cereal box

This problem needs to be divided into 3 situation:

Case 1, Where Hannah gets prize when she buys the first box:

Let K be the event of Hannah winning the prize on buying the first box.

⇒P(K)=P(A)=0.4

Case 2, Where Hannah gets prize when she buys the second box:

I<u>n this event Hannah should not get the prize in first box but should get the prize on buying the second box</u>

Let L be the event of Hannah winning the prize on buying the second box

So, P(L)=P(A')·P(A)

=(0.6)·(0.4)

=0.24

Case 3,Where Hannah gets prize when she buys the third box:

<u>In this event Hannah should not get the prize in first and second box but should get the prize on buying the third box</u>

Let L be the event of Hannah winning the prize on buying the third box

So, P(L)=P(A')·P(A')·P(A)

=(0.6)·(0.6)·(0.4)

=0.144

Let N be the event of Hannah winning the prize on buying 3 or less boxes before getting a prize

⇒N=K∪L∪M

Now, Required probability is P(N)=P(K∪L∪M)=P(K)+P(L)+P(M) [As events K,L and M are independent and disjoint events]

⇒P(N)=0.4+0.24+0.144

=0.784

7 0

3 years ago

A recipe calls for two dozen of 2 3/4 cups of sugar. How many cups of sugar do you need for 1 dozen?

Murljashka [212]

Answer:

1.37

Step-by-step explanation:

that is half of 2 and 3/4

5 0

3 years ago

The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged

Ganezh [65]

Answer:

a) P [ X < 24 mm ] = 0,3015 or P [ X < 24 mm ] = 30,15 %

b) P [ X > 32 mm ] = 0,1251 or P [ X > 32 mm ] = 12,51 %

c) P [ 25 < X < 30 ] = 0,4964 or P [ 25 < X < 30 ] = 49,64 %

d) z(s) = 0,84

Step-by-step explanation:

Normal Distribution N ( μ₀ ; σ ) is N ( 26,5 ; 4,8 )

a) P [ X < 24 mm ] = ( X - μ₀ ) / σ

P [ X < 24 mm ] = (24 - 26,5)/ 4,8 = - 0,5208 ≈ - 0,52

P [ X < 24 mm ] = - 0,52

And from z-table we find area for z score

P [ X < 24 mm ] = 0,3015 or P [ X < 24 mm ] = 30,15 %

b)P [ X > 32 mm ] = 1 - P [ X < 32 mm ]

P [ X < 32 mm ] = ( 32 - 26,5 ) / 4,8

P [ X < 32 mm ] = 5,5/4,8 = 1,1458 ≈ 1,15

P [ X < 32 mm ] = 1,15

And from z-table we get

P [ X < 32 mm ] = 0,8749

Then:

P [ X > 32 mm ] = 1 - 0,8749

P [ X > 32 mm ] = 0,1251 or P [ X > 32 mm ] = 12,51 %

c) P [ 25 < X < 30 ] = P [ X < 30 ] - P [ X < 25 ]

P [ X < 30 ] = 30 - 26,5 / 4,8 = 0,73

From z-table P [ X < 30 ] = 0,7673

P [ X < 25 ] = 25 - 26,5 / 4,8 = - 0,3125 ≈ - 0,31

From z-table P [ X < 25 ] = 0,2709

Then

P [ 25 < X < 30 ] = 0,7673 - 0,2709

P [ 25 < X < 30 ] = 0,4964 or P [ 25 < X < 30 ] = 49,64 %

d) If 20 %

z- score for 20% is from z-table

z(s) = 0,84

6 0

3 years ago