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kramer
3 years ago
5

In addition to age, the gomez score was originally based on the measurements of:

Mathematics
1 answer:
Musya8 [376]3 years ago
3 0
Measures of height
width does not matter
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At which values of x does the function f(x) have a vertical asymptote
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Answer:

A. 0

E. -3

F. 9

Step-by-step explanation:

You can't divide by 0; it is undefined. So if x cannot equal zero, then anything that turns the denominator to zero is an asymptote. Therefore, the roots of the cubic expression would be excluded, and we get our final answers.

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3 years ago
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jekas [21]

Answer:

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Step-by-step explanation:

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2 years ago
Find the value of x so that the function has the given value.<br><br> h(x) = 3x −5; h(x) = 4
Gwar [14]

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7

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4 0
3 years ago
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Simplify 5 square root of 7 end root plus 12 square root of 6 end root minus 10 square root of 7 end root minus 5 square root of
Sphinxa [80]
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4 0
3 years ago
What is the area of a rectangle with vertices at ​ (0, −4) ​, ​ (−1, −3) ​ , (2, 0) , and (3, −1) ? Enter your answer in the box
Bad White [126]

We are given vertices of a rectangle (0, −4) ​, ​ (−1, −3) ​ , (2, 0) , and (3, −1).

Length is the distance between (0, −4) ​and ​ (−1, −3) points.

Width is distance between  (−1, −3) ​ and (2, 0) points.

<u>Computing length:</u>

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

=\sqrt{\left(-1-0\right)^2+\left(-3-\left(-4\right)\right)^2}

=\sqrt{2}

<u>Computing Width :</u>

\mathrm{The\:distance\:between\:}\left(-1,\:-3\right)\mathrm{\:and\:}\left(2,\:0\right)\mathrm{\:is\:}

=\sqrt{\left(2-\left(-1\right)\right)^2+\left(0-\left(-3\right)\right)^2}

=3\sqrt{2}

<h3>Area of the rectangle = Length × Width  </h3>

= \sqrt{2} \times 3\sqrt{2} = 3 \times 2 = 6 \ squares \ units..


7 0
3 years ago
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