What is the slope of the line that passes through the points (-10, -8) and
2 answers:
Answer:
Equation: y = -4x + 32
Slope: -4
Step-by-step explanation:
Given : (-10,-8) and (-8, -16)
Slope Formula:
Solve For Slope, Input Given Points:
Solve for y-intercept:
Input the slope into the equation y = mx + b. Plugin x and y values for the x and y variables to find b.
- y = -4x + b
- -8 = -10(4) + b
- -8 = -40 + b
- b = 32
Equation of LIne: y = -4x + 32
-Chetan K
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Answer:
The inclination of the through the points (5, 14) and (9, 18) is 45°
Step-by-step explanation:
The given point has coordinates (5, 14) and (9, 18)
To find the inclination, θ, of the line passing the two points, with point 1 having coordinates (x₁, y₁) and point 2, having coordinates (x₂, y₂), we have to look for the slope as follows;
The slope, m = Change in the y-coordinate ÷ Change in the x-coordinate
Where:
y₁ = The y-coordinate of point 1 = 14
x₁ = The x-coordinate of point 1 = 5
y₂ = The y-coordinate of point 2 = 18
x₂ = The x-coordinate of point 2 = 9
Substituting, we have;
The inclination of the line is the angle the line makes with x-axis
Since the slope gives the ratio of the opposite and adjacent segment to the angle of inclination, the arc-tangent of the slope will give the angle in degrees as follows;
given that m = 1, we have;
tan⁻¹(m) = θ = tan⁻¹(1) = 45°.