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Pavel [41]
3 years ago
10

What is the volume of a rectangular prism with a length of 81\2 centimeters, width of 9 1\3 centimeters, and a height of 12 2\5

centimeters?
Mathematics
1 answer:
Alinara [238K]3 years ago
5 0
Hello!

We must use a certain formula to find the volume of a rectangular prism. The formula is:

V = l × w × h

Let's multiply the 3 dimensions together. Before we can do that, though, we must convert the mixed fractions to improper fractions.

8 1/2 = (8 × 2) + 1 / 2 = 17/2

9 1/3 = (9 × 3) + 1 / 3 = 28/3

12 2/5 = (12 × 5) + 2 / 5 = 62/5

17/2 × 28/3 = 476/6 (which can be simplified to 238/3)

238/3 × 62/5 = 14756/15

Final Answer:

The volume of the rectangular prism is 983 11/15 centimetres cubed, and 983.733 centimetres cubed (Repeating decimal) as a decimal.

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The answer is 6 and 1/15.
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Y_Kistochka [10]

Answer: division property of equality

Step-by-step explanation:

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6 0
3 years ago
Twice Henry's earnings increased by 10 is $253. Therefore, Henry earned $____
valina [46]

Answer:

121.50

Step-by-step explanation:

Let x be the earnings

2x+10 = 253

Subtract 10 from each side

2x+10-10 = 253-10

2x = 243

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8 0
3 years ago
Indicate which two quadrants “theta” could terminate if sin theta = 4/5
Nitella [24]

Answer:

1st and 2nd quadrants

Step-by-step explanation:

You have sine is positive since it is 4/5.

Sine is the y-coordinate.

On the coordinate plane y is positive in the 1st and 2nd quadrants.

8 0
3 years ago
Question 1
arlik [135]

Answer:

30

Step-by-step explanation:

This problem can be done without the Distance Formula (which is a way to find the distance between any two points in the plane).

The attached image shows the points and segments joining them.

PQ = 5 because the points are on the same horizontal line, and you can count spaces between them (or subtract x-coordinates: 4 - (-1) = 5).

PR = 12 because the points are on the same vertical line; count spaces or subtract y-coordinates, 7 - (-5) = 12.

The triangle is a right triangle, so the Pythagorean Theorem can be used to find the length of the hypotenuse.

(\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2

(QR)^2=5^2+12^2=25+144=169\\QR=\sqrt{169}=13

The perimeter of the triangle is 5 + 12 + 13 = 30

6 0
3 years ago
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