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2 years ago

Please help with this math

Mathematics

2 answers:

Nezavi [6.7K]2 years ago

6 0

Answer:

jqajgabaNJabba

Step-by-step explanation:

bjHBabBJajabanaa

liq [111]2 years ago

3 0

$x=2+½*\sqrt{10}$

$x=2-½*\sqrt{10}$

Answer:

Solution given:

y=2x²-5x+6.....[1]

y=3x+3.........….[2]

solving equation 1&2

2x²-5x+6=3x+3

2x²-5x-3x+6-3=0

2x²-8x+3=0

comparing above equation with ax²+bx+c=0 we get

a=2

b=-8

c=3

by using quadratic equation

$x=\frac{+8±\sqrt{(-8)²-4*2*3}}{2*2}$

$x=\frac{+8±2\sqrt{10}}{4}$

taking positive

$x=\frac{+8+2\sqrt{10}}{4}$

$x=2+½*\sqrt{10}$

taking negative

$x=2-½*\sqrt{10}$

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katen-ka-za [31]

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I really need help with this

ElenaW [278]

Number of boys:
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3 years ago

A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation A pizza delivery company buys

zubka84 [21]

Answer:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

$\mu = 34$ represent the mean

$\sigma= 5$ represent the deviation

We have a sample size of n = 54 and we want to find this probability:

$P(33.3 < \bar X< 34.3)$

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And we can use the z score formula given by:

$z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028$

$z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441$

An we can use the normal standard table and the following difference and we got this result:

$P(-1.028$

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