Evaluate 3(x+4)(x+1)/(x+2)(x-2) if x = 4 a.-10 B.10/3 C.-10/3 D.10

1 answer:

6 0

We would plug in x to all of those equations. So, 3(4+4)(4+1)/(4+2)(4-2). This would be 3(8)(5)/(6)(2). Then multiply them. 3(8)(5) would be 120. (6)(2) would be 12. Then divide 120 and 12 to get 10.

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The height of a triangle is 3cm less than twice the base. The area is 10cm2

Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

This is a solve the system question. Call H the height of the triangle and B the base. The question tells us:

$H=2B-3$

and

$\frac{B \times H}{2}=10$

Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

$\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4$

In this question, we take B=4. You can't have a negative side length so the other answer is eliminated. Now sub the value for B into either of the original equations. I'll use the first, again because H is already isolated:

$H=2(4)-3\\H=8-3\\H=5$