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Crank
3 years ago
11

A person throws darts at a dart board and the darts are spread all around the bullseye, but not grouped together in one general

area. What statement best describes this situation? A) The dart thrower is accurate and precise. B) The dart thrower isn't very accurate or precise. C) The dart thrower is accurate but not very precise. D) The dart thrower is precise but not very accurate. Eliminate
Biology
2 answers:
sweet-ann [11.9K]3 years ago
4 0
B because he was precise to get them all in the same are but not accurate to get any in the bullseye
Ymorist [56]3 years ago
4 0

Answer:

Answer C)

Explanation:

The person throwing the darts it is not successful in reaching the intended target, but the darts are around the bullseye, therefore the person is accurate. This person is not precise because the darts are not close to each other. This difference between precision and accuracy its used for scientific purposes.

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your answer is:

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The ability of the human body to break down the red color in beets is controlled by an autosomal dominant allele. The inability
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Answer:

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<em>Let the ability to break down the red color in beets be represented by the allele </em><em>B</em><em>. The inability would be represented by the allele </em><em>b</em><em>.</em>

A nonsecretor's genotype would be BB or Bb while a secretor's genotype would be bb.

A nonsecretor woman with a secretor father would be a carrier with genotype Bb. A nonsecretor man who in a previous marriage had a secretor daughter would also be a carrier with genotype Bb. If the two marries:

            <em>Bb     x     Bb</em>

<em>            BB    2Bb    bb</em>

1.

(a) probability of their first child will be a secretor girl = probability of having a girl and being a secretor.

Probability of having a girl = 1/2

Probability of being a secretor = 1/4

<em>probability of their first child will be a secretor girl</em> = 1/2 x 1/4 = 1/8

(b) Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor.

Probability of having a girl = 1/2

Probability of being a nonsecretor = 3/4

<em>Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor</em> = 1/2 x 3/4 = 3/8

2. <em>Probability that their first two children will be nonsecretors of either sex = probability of their first being a nonsecretor and of either sex and probability of their second being a nonsecretor and of either sex.</em>

  = 3/4 x 3/4 = 9/16

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Okay First off what are the problems and what are the hardest ones?
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