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3 years ago

For a set of data, r = 0.27. Which is true about the correlation of the variables?

Mathematics

2 answers:

Harman [31]3 years ago

6 0

The correlation is a weak positive correlation

weqwewe [10]3 years ago

4 0

Answer:

Step-by-step explanation:

In statistics, association is any statistical relationship, whether causal or not, between two random variables or bivariate data. One is independent and other is dependent variable. In the broadest sense correlation is any statistical association, though in common usage it most often refers to how close two variables are to having a linear relationship with each other.

Examples are exercise and sickness are negatively correlated.

Study hours and marks are positively correlated

When correlation is nearer -1 or +1 there is a strong correlation. When correlation is nearer to 0 than to 1 or -1 we say that there is a negative correlation.

Here sign of r is positive.

Hence there is a positive and weak correlation.

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In-s [12.5K]

Answer:

5x^7y^11.

Step-by-step explanation:

∛(125x^21 y^33)

The cube root = 'to the power 1/3' so we have:

125^1/3 * x^(21*1/3) * y^(33*1/3)

5x^7y^11.

6 0

3 years ago

What are the answers to this? PLEASE HELP.

shepuryov [24]

Answer:

Ray : Line NA, Line NB, Line AB

Vertex : Vertex N

Angle: Angle ANB

Parallel Lines: None

Coplanar Points: Points C, A, F, N, B

Collinear Points: Points A, N, B

Segment Addition Postulate: AN + NB = AB

Perpendicular Lines: None

6 0

3 years ago

Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2

Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

$\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)$ .

The sine difference identity is:

$\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a)$ .

The cosine addition identity is:

$\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ .

The cosine difference identity is:

$\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)$ .

We need to find a way to put some or all of these together to get:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$ .

So I do notice on the right hand side the $\sin(a+b)$ and the $\sin(a-b)$ .

Let's start there then.

There is a plus sign in between them so let's add those together:

$\sin(a+b)+\sin(a-b)$

$=[\sin(a+b)]+[\sin(a-b)]$

$=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]$

There are two pairs of like terms. I will gather them together so you can see it more clearly:

$=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]$

$=2\sin(a)\cos(b)+0$

$=2\sin(a)\cos(b)$

So this implies:

$\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)$

Divide both sides by 2:

$\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)$

By the symmetric property we can write:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$

3 0

3 years ago

Insert parenthesis in the following problem to make it true.

suter [353]

Answer:

(7-2) x 2 -1 = 9

Step-by-step explanation:

(7-2) = 5 x 2 =10 -1 = 9

6 0

3 years ago

The manager of a bank recorded the amount of time each customer spent waiting in line during peak business hours one Monday. The

zavuch27 [327]

The standard deviation of the frequency distribution is 5.54

<h3>How to determine standard deviation?</h3>

The table of values is given as:

x f(x)

0-3 13

4-7 13

8-11 10

12-15 11

16-19 0

20-23 3

Rewrite the table by calculating the class midpoints:

x f(x)

1.5 13

5.5 13

9.5 10

13.5 11

17.5 0

21.5 3

Start by calculating the mean using:

$\bar x = \frac{\sum fx}{\sum f}$

This gives

$\bar x = \frac{1.5 * 13 + 5.5 * 13 + 9.5 * 10 + 13.5 * 11 + 17.5 * 0 + 21.5 * 3}{13 + 13 + 10 + 11 + 0 +3}$

Evaluate

$\bar x = 7.98$

The standard deviation is then calculated as:

$\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f }}$

So, we have:

$\sigma= \sqrt{\frac{13 * (1.5 - 7.98)^2 + 13 * (5.5 - 7.98)^2 + (9.5 - 7.98)^2 * 10 + (13.5 - 7.98)^2 * 11 + (17.5 - 7.98)^2 * 0 + (21.5 - 7.98)^2 * 3}{13 + 13 + 10 + 11 + 0 +3}}$

Evaluate

$\sigma= \sqrt{30.6496}$

Solve

$\sigma= 5.54$

Hence, the standard deviation is 5.54

Read more about standard deviation at:

brainly.com/question/15858152

#SPJ1

7 0

1 year ago