This problem deals with a weighted average. Since the AP classes count twice as much as regular classes, their grades must be counted twice. It's as if for each AP class he's taking, he was taking two classes. The points of each AP class grade is added twice, and the each AP class counts as 2 classes in the number of classes.

Each AP class counts twice and counts as 2 classes.

Class                                Ben's grade     Points          Number of Classes
AP English                               B 3 + 3 2
AP Government      B 3 + 3 2
AP Algebra II                           A 4 + 4 2
Spanish B 3 1
Physics D 1 1
TOTALS 24 8

GPA = (total points)/(number of classes) = 24/8 = 3

<span>Answer: B 3.0</span>

7 0

3 years ago

PLEASE PLEASE HELP!! Sketch a triangle and label correctly. Work must be shown for this problem. Round answers to the nearest hu

torisob [31]

Answer:

Please see attached image for the sketch with the labels.

Length "x" of the ramp = 11.70 ft

Step-by-step explanation:

Notice that the geometry to represent the ramp is a right angle triangle, for which we know one of its acute angles ( $20^o$ ), and the size of the side opposite to it (4 ft). Our unknown is the hypotenuse "x" of this right angle triangle, which is the actual ramp length we need to find.

For this, we use the the "sin" function of an angle in the triangle, which is defined as the quotient between the side opposite to the angle, divided by the hypotenuse, and then solve for the unknown "x" in the equation:

$sin(20^o)=\frac{opposite}{hypotenuse}\\ sin(20^o)=\frac{4}{x} \\x=\frac{4}{sin(20^o)} \\x=11.695\,\,ft$