lol 5/9 because 5 out of the 9 are drinking punch, the other 4 are drinking lemonade.
The median is 38.5
The lower quartile is 29
There is an outlier (154)
The upper quartile is 70
and
The interquartile range is 70 - 29 = 41
Answer:
1.48
Step-by-step explanation:
4 times 2 = 8
4 minus 3 = 1
Answer:
![(Lower=0.61, Upper=0.91)](https://tex.z-dn.net/?f=%20%28Lower%3D0.61%2C%20Upper%3D0.91%29%20)
And using the property of symmetry for the confidence interval we can estimate the sample proportion
with this formula:
![\hat p =\frac{Upper-Lower}{2}= \frac{0.91-0.61}{2}= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%5Cfrac%7BUpper-Lower%7D%7B2%7D%3D%20%5Cfrac%7B0.91-0.61%7D%7B2%7D%3D%200.15)
The final answer for this case would be:
![\hat p= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%3D%200.15)
So approximately 15% of teenagers have a sibling.
Step-by-step explanation:
For this case we assume that the proportion of interest is
who represent the number of teenagers who have a sibling and in order to estimate this proportion we can conduct a confidence interval.
The confidence interval for the mean is given by the following formula:
And for this case the confidence interval is given by:
![(Lower=0.61, Upper=0.91)](https://tex.z-dn.net/?f=%20%28Lower%3D0.61%2C%20Upper%3D0.91%29%20)
And using the property of symmetry for the confidence interval we can estimate the sample proportion
with this formula:
![\hat p =\frac{Upper-Lower}{2}= \frac{0.91-0.61}{2}= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%5Cfrac%7BUpper-Lower%7D%7B2%7D%3D%20%5Cfrac%7B0.91-0.61%7D%7B2%7D%3D%200.15)
The final answer for this case would be:
![\hat p= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%3D%200.15)
So approximately 15% of teenagers have a sibling.