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3 years ago

STOP NEGATIVE TALKING

Mathematics

1 answer:

Likurg_2 [28]3 years ago

3 0

Answer:

Okay I guess I can watch that

thx for the points :)

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PLSSS HELP IMEDEATLY Find the x- and y-intercepts of the graph of 2 – 6y = 35. State your answers as

Lelechka [254]

Answer:

Y= -5.5 There is no X intercept.

Step-by-step explanation:

Please mark brainliest.

7 0

3 years ago

Which of the expressions below could be factored quickly using the "difference of squares"? Select all that apply.

boyakko [2]

Answer:

Difference of squares method is a method that is used to evaluate the difference between two perfect squares.

For example, given an algebraic expression in the form:

can be factored as follows:

From the given expressions, the only expression containing two perfect squares with the minus sign in the middle is the expression in option A.

i.e.

which can be factored as follows:

3 0

3 years ago

Read 2 more answers

Which values are solutions to K-3 >-2? Select two options.

Ierofanga [76]

Step-by-step explanation:

k‒3>‒2=k>‒2+3

=k>1

so there is not the answer here

5 0

3 years ago

What is the exact area of a circle with a diameter of 10 cm? a. 5πcm^2 b. 10πm^2 c. 25πcm^2 d. 100πcm^2

dalvyx [7]

Answer:

Step-by-step explanation:

a= $\pi$ r^2

To find the radius, divide the diameter by 2

r=d/2

r=10/2

r=5

a= $\pi$ r^2

a= $\pi$ 5^2

a=25 $\pi$

So, choice C is correct

Hope this helps! :)

4 0

3 years ago

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago