Exponential growth of the form:
F=Ar^t
F=100(1.22)^t
F(5)=100(1.22)^5
F(5)=270.27
F(5)=270 to the nearest frog...
....
1.22=r^12
r=1.22^(1/12)
F=100(1.22^(1/12)^t)
F=100(1.22^(t/12)) now it will produce monthly populations...
Say we did the same as before but instead of 5 years you have 60 months...
F(60)=100(1.22^(60/12))
F(60)=270 to the nearest frog... :P
The answer is: A) They are relatively prime. This is because both of them aren't divisible by any other number than 1. (or 0 if you really want to do that)
Answer:
subtract 20 on both sides then that should give you the answer
Step-by-step explanation:
21.325 is the correct answer
Answer:
<h2>x = 28</h2><h2>CE = 132</h2><h2 />
Step-by-step explanation:
|<------------- CE -------------------->|
C-------------------D-------------------E
2x + 10 3x - 18
2x + 10 = 3x - 18
2x - 3x = -18 - 10
-x = -28
x = 28
CE = 2x + 10 + 3x - 18
CE = 2(28) + 10 + 3(28) - 18
CE = 56 + 10 + 84 - 18
CE = 132
