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3 years ago

How do you solve this problem: 5(x3)-(-20)

1 answer:

8 0

First step: multiply the 5(x3) and it will give you x15 or most commonly written as 15x. you should now have 15x-(-20).

Second step: since you cannot subtract -20 from 15x because it has a variable, the final answer is just 15x-(-20), or 15x+20.

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A jacket originally cost $30.75. It went on sale for 20% off the original price. What was the sale price of the jacket?

gladu [14]

We have to calculate the 20% of $30.75
The 20% of $30.75=(20/100)*$30.75=(20*$30.75)/100=$6.15

The sale price of the jacket was $6.15.

6 0

3 years ago

Evaluate 3_/2 x 5_/2 .....(root)

Nostrana [21]

$( \frac{3}{2} )( \frac{5}{2}) = \frac{15}{2} or \sqrt{15} = 3.8 or 4$

3 0

3 years ago

Which sequence of transformations produces R’S’T’ from RST?

inn [45]

Answer:

A translation 2 units right and then a reflection over the x-axis

Step-by-step explanation:

The given vertices of ΔRST are R(0, 0), S(-2, 3), and T(-3, 1)

The vertices of triangle ΔR'S'T' are (2, 0), (0, -3), (-1, -1)

The points are plotted with the aid of MS Excel, and by observation, we have that the image of ΔRST is located on the other side of the x-axis with each coordinate on ΔR'S'T' shifted 2 units to the right of ΔRST

A translation of ΔRST 2 units right gives;

(0 + 2, 0) = (2, 0), (-2 + 2, 3) = (0, 3), and (-3 + 2, 1) = (-1, 1), to give;

(2, 0), (0, 3), and (-1, 1)

A reflection of the point (x, y) across the x-axis gives (x, -y)

A reflection of the above points across the x-axis gives;

(2, 0) reflected about x-axis → (2, 0) reflected about x-axis → (0, -3), and (-1, 1) reflected about x-axis → (-1, -1), which are the points of ΔR'S'T'

Therefore, the sequence of transformations that produces R'S'T' from RST are;

A translation 2 units right and then a reflection over the x-axis

6 0

3 years ago

The perimeter of a regular hexagon is 78 cm .What will be the length of each side?

k0ka [10]

Answer:

13 cm

Step-by-step explanation:

78/6=13

7 0

2 years ago

Read 2 more answers

Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution

Iteru [2.4K]

Consider the equation:

$\sqrt{x+2}+4 = 8$

Subtracting '4' from both the sides of the equation, we get as

$\sqrt{x+2}+4-4= 8-4$

$\sqrt{x+2}= 4$

Squaring on both the sides of the equation, we get

$(\sqrt{x+2})^2 = (4)^2$

$x+2 = 16$

Subtracting '2' from both the sides of the equation, we get

$x+2-2=16-2$

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

4 0

3 years ago

Read 2 more answers