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SOVA2 [1]
3 years ago
6

Can someone please explain this problem to me idk what I am doing wrong and can you draw the problem for me thanks

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

  you're not doing anything wrong

Step-by-step explanation:

In order for cos⁻¹ to be a function, its range must be restricted to [0, π]. The cosine value that is its argument is cos(-4π/3) = -1/2. You have properly identified cos⁻¹(-1/2) to be 2π/3.

__

Cos and cos⁻¹ are conceptually inverse functions. Hence, conceptually, cos⁻¹(cos(x)) = x, regardless of the value of x. The expected answer here may be -4π/3.

As we discussed above, that would be incorrect. Cos⁻¹ cannot produce output values in the range [-π, -2π] unless it is specifically defined to do so. That would be an unusual definition of cos⁻¹. Nothing in the problem statement suggests anything other than the usual definition of cos⁻¹ applies.

__

This is a good one to discuss with your teacher.

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Answer:

D) (10,22)

Step-by-step explanation:

based on given slope and point, the linear equation is <em>y = 9/5x + 2</em>

plugging in x-and-y values only results in a true statement for option D

example:

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6 0
3 years ago
A store charges 7% sales tax. Which expression can be used to find the total cost of an item with a price of p?
sergiy2304 [10]

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Step-by-step explanation:

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3 years ago
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wel

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3 years ago
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3 years ago
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Ilia_Sergeevich [38]

Answer:

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that's it dear

give my answer a brainliest

6 0
2 years ago
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