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SOVA2 [1]
3 years ago
6

Can someone please explain this problem to me idk what I am doing wrong and can you draw the problem for me thanks

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

  you're not doing anything wrong

Step-by-step explanation:

In order for cos⁻¹ to be a function, its range must be restricted to [0, π]. The cosine value that is its argument is cos(-4π/3) = -1/2. You have properly identified cos⁻¹(-1/2) to be 2π/3.

__

Cos and cos⁻¹ are conceptually inverse functions. Hence, conceptually, cos⁻¹(cos(x)) = x, regardless of the value of x. The expected answer here may be -4π/3.

As we discussed above, that would be incorrect. Cos⁻¹ cannot produce output values in the range [-π, -2π] unless it is specifically defined to do so. That would be an unusual definition of cos⁻¹. Nothing in the problem statement suggests anything other than the usual definition of cos⁻¹ applies.

__

This is a good one to discuss with your teacher.

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6 0
3 years ago
Among all pairs of numbers with a sum of 105 , find the pair whose product is maximum. Write your answers as fractions reduced t
Bond [772]

Answer: Hence Pair( x, y) = [ 105/2, 105/2]

Step-by-step explanation:

Given that;

Among all pairs of numbers with a sum of 105;

the pair whose product is maximum = ?

so let pairs of numbers with a sum of 105 be x and y respectively

x + y = 105

let y = 105 - x

now

product = xy =  x( 105 - x ) = 105x - x²

now

p(x) = 105x - x²

for maximum value of p

dp/dx =0

⇒ dp/dx = 105 - 2x = 0

2x = 105

x = 105/2

y + x = 105

y = 105 - x

y = 105 - 105/2 = 105/2

Hence Pair( x, y) = [ 105/2, 105/2]

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Step by step:
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3 years ago
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