Question

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Answer 1

The diet will include 123.75 daily grams of protein

Further explanation

One variable linear equation is an equation that has a variable and the exponent number is one.  

Can be stated in the form:  

$\large{\boxed{\bold{ax=b}}$

or  

ax + b = c, where a, b, and c are constants, x is a variable  

We complete the task :

A nutritionist planning a diet for a football player wants him to consume 3,500 Calories and 725 grams of food daily. Calories from fat and protein will be 45% of the total Calories. There are 4, 4, and 9 Calories per gram for protein, carbohydrates, and fat, respectively. How many daily grams of protein will the diet include?

• 243.75
• 481.25
• 123.75
• 120

Calories from fat and protein will be 45% (0.45) of the total Calories

Calories from fat and protein = 0.45 x 3500 = 1575 calories

Calories from carbohydrates = 3500 - 1575 = 1925 calories

So mass for carbohydrates = 1925 : 4(4 calories/gram) = 481.25 grams

Then mass for fat and protein = 725 - 481.25 = 243.75 grams

We can make equation for fat and protein

1. 4 calories. mass of protein(p) + 9 calories . mass of fat(f) = 1575 calories

2. mass of protein(p) + mass of fat(f) = 243.75

we can simplify :

1. 4p+9f = 1575

2. p + f = 243.75 ⇒ f = 243.75 - p

we substitute equation 2 into equation 1 :

4p + 9(243.75-p) = 1575

4p + 2193.75-9p=1575

-5p = -618.75

p = 123.75

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linear equation

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Keywords : one variable, linear equation ,diet, nutritionist,calories, fat, proteins, carbohydrates, daily grams

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