Radius of curvature = 10'
Diameter of circle = 2 * 10' = 20'
height of segment = 2'
Let semi-chord be x.
Then by the intersecting chord property,
2*(20-2)=x^2
x^2=36
x=sqrt(36)=6
=>
chord=2x=2*6=12'
Answer: 84 degrees
Step-by-step explanation: I'm not quite sure how to explain this problem, sadly, but you basically add up the degrees together in the big triangle all together, and then figure out the rest.
Answer:
30003/50000
Step-by-step explanation:
The final '3' in 30003/50000 makes this fraction just slightly greater than 3/5.
Answer:
-2
Step-by-step explanation:
Put the given value in the equation and solve for x.
f(x) = 12
f(x) = 2(x +8)
12 = 2(x +8) . . . . . use 12 for f(x)
6 = x +8 . . . . . . . . divide by 2
-2 = x . . . . . . . . . . subtract 8
Answer:
a) bijective
b) neither surjective or injective
c) injective
Step-by-step explanation:
Since we are looking from real numbers to real numbers, we want the following things
1) We want every real number y to get it. (surjective)
2) We want every y that gets hit to be hit only once. (injective).
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If we have both things then the function is bijective.
a) f(x)=5x+4 this is a line with a positive slope.
That means it is increasing left to right. Every increasing or even decreasing line is going to hit every real number y. This is a bijection.
b) g(x)=2x^2-2 is a parabola. Parabola functions always have y's that get hit more than once and not all y's get hit because the parabola is either open up or down starting from the vertex. This function is neither injective or surjective.
c) h(x)=1+(2/x) x is not 0.
1+(2/x) is never 1 because 2/x is never 0 for any x. This means the real number y=1 will never be hit and is therefore not surjective. This function is injective because every 1 that is hit is only hit once. If you want use the horizontal line test to see this.