Ask question

Ask question

All categories

3 years ago

5

The price of a house is originally listed at $205,000. The owners are having a hard time selling it and decide to reduce the pri

ce to $149,650. What is the percentage decrease of the price of the house?

1 answer:

VARVARA [1.3K]3 years ago

3 0

Answer:

The percentage decrease is 27%

Step-by-step explanation:

To find the percent decrease, first find the difference in the two costs.

$205,000 - $149,650 = $55,350

Now divide that number by the original cost.

$55,350/$205,000 = 27%

You might be interested in

Five students ran in their schools field day competition. Chris beat Allie by 7 yards but he was 2 yards behind Elena. Derrick f

anzhelika [568]

From last place to first BART was last the it was DERRICK, ALLIE, and CHRIS and ELENA in first. I hope this helps you!

4 0

3 years ago

Mr. Brown chooses a fiction book at random from a list of books and then chooses a second fiction book from those remaining.

fgiga [73]

Independent would be when Mr. Brown chooses a fiction boom at random from a list of books.

Dependent would be when Mr.Brown then chooses a second fiction. book from those remaining.

5 0

2 years ago

Read 2 more answers

If 1900 square centimeters of material are available to make a box with a square base and an open top, find the largest possible

Evgen [1.6K]

Answer:

Volume = $7969$ cubic centimeter

Step-by-step explanation:

Let the length of each side of the base of the box be A and the height of the box be H.

Area of material required to make the box is equal to is $A^2 + 4*A*H.$

$A^2 + 4*A*H = 1900$

Rearranging the above equation, we get -

$`H = \frac{(1900 - A^2)}{(4*A)}$

Volume of box is equal to product of base area of box and the height of the box -

$V = A*A* H$

Substituting the given area we get -

$\frac{A^2*(1900 - A^2)}{4A} = \frac{(1900*A - A^3)}{4}$

For maximum volume

$\frac{dV}{dA} =0$

$\frac{ 1900}{4} - \frac{3*A^2}{4} = 0$

$A^2 = \frac{1900}{3}$

Volume of the box

= $\frac{\frac{1900}{3}*(1900 - \frac{1900}{3}) }{4 * \sqrt{\frac{1900}{3} } }$

= $7969$ cubic centimeter

3 0

2 years ago

Determine the range of the function.

Naya [18.7K]

Answer:

$Solution: f(x)\ge-5\\Interval:[-5,\infty)$

Step-by-step explanation:

Equation: $\frac{1}{4} x^2-5 = y$

1). $\frac{1}{4} x^2-5 = y$ → $\frac{x^2}{4}-5=y$

2). $\frac{x^2}{4}-5=y$ ∴ $a=\frac{1}{4}, b=0, c=-5$

3). $x_v=-\frac{b}{2a}$

$=-\frac{0}{2(\frac{1}{4})}$

$=0$

4). now plug $x_v$ into $y_v$

$y_v=\frac{0^2}{4}-5$

$=-5$

5). Minimum (0,-5) ∴ $f(x)\ge-5$

4 0

3 years ago

Given the triangle that has a base of five less than triple the height. The height is 2x+6.

Deffense [45]

Answer:

<h3> A = 0.5(2x+6)(6x+13) = 6x² + 49x + 78</h3>

Step-by-step explanation:

H = 2x+6 - the hight

3H = 3(2x+6) - triple the hight

3H-5 = 3(2x+6) - 5 - five less than triple the height

Area of triangle: A = 0.5BH

B = 3(2x+6)-5 = 6x + 18 - 5 = 6x + 13

H = 2x+6

So:

A = 0.5(2x+6)(6x+13) = (x+6)(6x+13) = 6x² + 13x + 36x + 78

A = 6x² + 49x + 78

5 0

2 years ago